AppleScript 焦点/重命名文件(并单击任意位置)
on run {input}
set filepath to POSIX path of input
do shell script "touch " & quoted form of filepath & "untitled"
return input
end run
这是我到目前为止所拥有的,并且它有效,但是有没有办法然后专注于文件然后触发重命名?我不希望自动重命名,只需触发事件(例如在选择文件时按“返回”)。我不想使用任何类型的模式...
快速侧面问题:有没有办法设置它,以便我不必直接选择文件夹或文件,但可以通过以下方式来完成:比方说,只要文件夹位于 Finder 中,就单击该文件夹中的空白区域?现在,我已在 Finder.app
中将“服务接收选定”设置为“文件或文件夹
”。
==更新的代码==
on run {input}
set filepath to POSIX path of input
do shell script "touch " & quoted form of filepath & "untitled"
tell application "Finder"
activate
set target of Finder window 1 to POSIX file "/Users/oscargodson/Documents/designs/untitled"
end tell
tell application "System Events"
tell process "Finder"
keystroke return
end tell
end tell
return input
end run
如果我硬编码它的工作路径!但是我如何才能将它作为一个有效的 var
呢?
on run {input}
set filepath to POSIX path of input
do shell script "touch " & quoted form of filepath & "untitled"
return input
end run
Is what I have so far, and it works, but is there a way to then focus on the file then trigger a rename? I dont want the rename to be automatic, just trigger the event (like pressing "return" while you have a file selected). And I dont want to use any sort of modal...
Quick Side question: is there a way to set this so that i dont have to select a folder or file directly, but can do it by, lets say, clicking in a white space in a folder as long as it's in Finder? Right now I have my "Service receives selected" to "files or folders
" in Finder.app
.
== UPDATED CODE ==
on run {input}
set filepath to POSIX path of input
do shell script "touch " & quoted form of filepath & "untitled"
tell application "Finder"
activate
set target of Finder window 1 to POSIX file "/Users/oscargodson/Documents/designs/untitled"
end tell
tell application "System Events"
tell process "Finder"
keystroke return
end tell
end tell
return input
end run
If i hardcode the path it works! But how do I get it as a var
that works?
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这是一种方法。我认为询问名称的模态窗口会更好,但你可以尝试这个。请注意,您在此代码中没有使用“POSIX 路径”。 Applescript 不使用 POSIX 路径。另外,{input}(如括号所示)是一个项目列表。因此,您对列表中的项目进行操作,在本例中,我们对第一项进行操作。
编辑:使用更新后的代码,这是一个工作脚本...
Here's one way. I think a modal window where you ask for the name would be better but you can try this. Notice you do not use "POSIX path" in this code. Applescript doesn't use POSIX paths. Also {input}, as indicated by the brackets around it, is a list of items. Therefore you act on the items of the list, and in this case we act on the first item.
EDIT: With your updated code, here's a working script...
reveal
和select
始终打开一个新窗口,set target
和set Selection
则不会。我不知道为什么,但是当在列视图中使用
设置选择
时,您只能选择前窗口目标的全部内容中的项目。同样的事情在其他视图中不会发生,所以这看起来像是一个错误。修复已编辑问题中的代码:(
on go
和最后几行仅用于测试。)reveal
andselect
always open a new window,set target
andset selection
don't.I don't know why, but when
set selection
it used in column view, you can only select items in the entire contents of the target of the front window. The same thing doesn't happen in other views, so it seems like a bug.Fix for the code in the edited question:
(That
on go
and the last lines are just for testing.)我基于 @regulus6633 的 AppleScript 创建了一个 AppleScript,但进行了一些改进。
注意:此答案最初作为询问不同答案发布。为了方便起见,我在这里复制/粘贴。
我们的想法是创建一个 Automator 工作流程,并使用以下步骤为其分配快捷方式:
现在,让我们展示 AppleScript:
为了方便起见,我将此 AppleScript 放在 此 GitHub Gist 中。
I've created an AppleScript based on the @regulus6633's one, but with some improvements.
Note: This answer was originally posted as an AskDifferent answer. I'm copy/pasting here for convenience.
The idea is to create an Automator workflow and assigning a shortcut to it using the following steps:
Now, let's show the AppleScript:
For convenience, I'm putting this AppleScript in this GitHub Gist.