XPATH 查询查找包含关键字的属性
我正在尝试在多个不同节点的多个属性中搜索某些内容
这就是我在一个属性中找到它的方式
//*[contains(@name,'KEYA')]
示例 XML：
<cars>
<car model="2000" name="Awesome KEYA Car" name2="somethine else">Brand1</car>
<car model="2005" name="Awesome Car" name2="KEYA something else">Brand 2</car>
<car name="Awesome Car" name2="somethine else">Brand1</car>
<car dontmatch="KEYA" name2="somethine else">Brand3333</car>
</cars>
我真正想要的是超过 10 个属性的类似内容（它只需要匹配白名单属性） ，
//*[contains((@name or @name2 or @name3),'KEYA')]
使用XPATH 1.0。关于如何做到这一点有什么想法吗？除了重复包含之外尝试了多种方法，但没有成功。
I'm trying to search something in multiple attributes in multiple different nodes
This is how I find it in one attribute
//*[contains(@name,'KEYA')]
Sample XML:
<cars>
<car model="2000" name="Awesome KEYA Car" name2="somethine else">Brand1</car>
<car model="2005" name="Awesome Car" name2="KEYA something else">Brand 2</car>
<car name="Awesome Car" name2="somethine else">Brand1</car>
<car dontmatch="KEYA" name2="somethine else">Brand3333</car>
</cars>
What I really want is something like this for more than 10 attributes (it needs to match only white-listed attributes),
//*[contains((@name or @name2 or @name3),'KEYA')]
Using XPATH 1.0. Any ideas about how to do this? Tried several ways other than repeating contains but didn't work.
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这对我有用
好的，编辑后，我建议
如果您想排除多个属性，则需要指定其他谓词（方括号内的内容）。 Xpath 不提供排除属性名称集的方法，除非您可以使用
startswith()或contains()或类似的东西来约束该集合。有一些方便的方法可以在其他库中查询 XML，例如，如果您使用 .NET，则可以使用 LINQ-to-XML。这将允许您更简洁地指定这些类型的查询。但它是一个完全不同的 API。
This worked for me
ok, after the edit, then I suggest
If you want to exclude more than just one attribute, then you need to specify additional predicates (the things inside the square brackets). Xpath doesn't provide a way to exclude sets of attr names, unless you can constrain the set with a
startswith()orcontains()or something similar.There are handy ways to query XML in other libraries, like, for example LINQ-to-XML if you are using .NET. That would allow you to specify those kinds of queries more succintly. But it's a different API altogether.
使用：
这是由 XPath 可视化工具：
说明 :
您可以在字符串中指定要搜索的所有属性的名称。使用的“管道分隔符 (
|) 保证即使一个名称是另一个名称的开头，只有当该名称存在单独的管道分隔子字符串时，该名称才会包含在搜索中。Use:
Here is the selection, as produced by the XPath Visualizer:
Explanation:
You can specify in a string the names of all attributes you want searched. The "pipe delimiter (
|) used guarantees that even if a name is the start of another, it one will only be included in the search if there is a separate, pipe-delimited substring for this name.怎么样：
您可以采用 Cheeso 的答案并执行以下操作：
您必须以某种方式构建 XPath 语句，以从属性白名单中进行选择（我的示例），或者排除黑名单中的属性（修改后的 Cheeso 示例）。
再次构建 Cheeso 的工作，这可能会简化构建黑名单：
//@*[contains(.,'KEYA') and not(contains('dontmatch,dontmatch2', local-name()))]/parent::*或作为白名单：
//@*[contains(.,'KEYA') and contains('name,name2', local-name())]/parent::**How about:
You could take Cheeso's answer and do something like this:
One way or another you're going to have to construct the XPath statement to either select from a whitelist of attributes (my example), or exclude attributes in a blacklist (the modified Cheeso example).
Building again off of Cheeso's work this might simplify building the blacklist:
//@*[contains(.,'KEYA') and not(contains('dontmatch,dontmatch2', local-name()))]/parent::*or as a whitelist:
//@*[contains(.,'KEYA') and contains('name,name2', local-name())]/parent::**