Mod 重写正则表达式，仅在前一个子集匹配时才匹配
我正在尝试制作一个我认为与 mod_rewrite 一起使用的简单正则表达式。
我尝试过各种表达方式，其中许多我认为很有希望，但最终都因为这样或那样的原因失败了。一旦我添加开始/结束字符串分隔符，它们似乎也会失败。
例如， ^user/(\d{1,10})(?=/)$ 是我尝试过的一个，但除此之外，它似乎对尾部斜杠进行了分组，我只想对数字进行分组。我认为我需要使用积极的回顾，但我遇到了困难，因为它是在回顾一个群体。
我想要匹配的是 1) 以“user/”开头和 2) 可能以 (\d{1,10})/ 结尾的字符串（1 到 10 位数字后跟一个斜杠)
应该匹配：
user/
user/123/
user/1234567890/
不应该匹配：
user
user//
user/-4/
user/35.5/
user/123
user/123//
user/123/5/
user/12345678901/
编辑：对格式感到抱歉；我不明白如何通过此降价格式化任何内容。这些示例前面有 4 个空格，我认为它们应该构成一个代码块，但显然我的想法是错误的。
I am trying to make what I think is a simple regex for use with mod_rewrite.
I've tried various expressions, many of which I thought were promising, but all of which ultimately failed for one reason or another. They all also seem to fail once I add start/end string delimiters.
For example, ^user/(\d{1,10})(?=/)$ was one I tried, but among other things, it seems to group the trailing slash, and I only want to group the digits. I think I need to use a positive lookbehind, but I'm having difficulty because it's looking behind at a group.
What I am trying to match is strings that 1) begin with "user/" and 2) possibly end with (\d{1,10})/ (1 to 10 digits followed by a single slash)
Should Match:
user/
user/123/
user/1234567890/
Should not match:
user
user//
user/-4/
user/35.5/
user/123
user/123//
user/123/5/
user/12345678901/
Edit: Sorry about the formatting; I do not understand how to format anything via this markdown. Those examples are preceded by 4 spaces which I thought should make a code block, but obviously I thought wrong.
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评论（2）
^user/(?:([0-9]{1,10})/)?$应该可以正常工作。^user/(?:([0-9]{1,10})/)?$should work just fine.这是：
^user(?=/)(/\d{1,10})?/$编辑：如果要对数字进行分组，^user(?=/)(? :/(\d{1,10}))?/$This:
^user(?=/)(/\d{1,10})?/$Edit: if you want to group digits,^user(?=/)(?:/(\d{1,10}))?/$