SQL SERVER：获取两个日期之间的总天数

Question

我试图获取两天之间的总天数：

1/1/2011
3/1/2011

RETURN
62

Is it possible to do in SQL Server?

Answer 1

PRINT DATEDIFF(DAY, '1/1/2011', '3/1/2011') 会给你你想要的。

这给出了两个日期之间跨越午夜边界的次数。如果您将两个日期都包含在计数中，您可能会决定需要加一；如果您不想包含任一日期，则可能需要减一。

Answer 2

SQL Server DateDiff

DECLARE @startdate datetime2 = '2007-05-05 12:10:09.3312722';
DECLARE @enddate datetime2 = '2009-05-04 12:10:09.3312722'; 
SELECT DATEDIFF(day, @startdate, @enddate);

Answer 3

您可以尝试这个 MSDN 链接

DATEDIFF ( datepart , startdate , enddate )
SELECT DATEDIFF(DAY, '1/1/2011', '3/1/2011')

Answer 4

请参阅 DateDiff：

DECLARE @startdate date = '2011/1/1'
DECLARE @enddate date = '2011/3/1'
SELECT DATEDIFF(day, @startdate, @enddate)

Answer 5

另一种日期格式

select datediff(day,'20110101','20110301')

Answer 6

SELECT DATEDIFF(day, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');

Answer 7

这对我有用 -

SELECT DATEDIFF(DAY, startdate, enddate) AS DayCount

Example : SELECT DATEDIFF(DAY, '11/30/2019', GETDATE()) AS DayCount

Answer 8

如果您想做同样的事情存储过程那么您需要应用下面的代码。

select  (datediff(dd,'+CHAR(39)+ convert(varchar(10),@FromDate  ,101)+ 
 CHAR(39)+','+CHAR(39)+ convert(varchar(10),@ToDate  ,101) + CHAR(39) +')) 
 Daysdiff

其中@fromdate和@todate是SP的参数

Answer 9

DECLARE @FDate DATETIME='05-05-2019' /*This is first date*/
 GETDATE()/*This is Current date*/
SELECT (DATEDIFF(DAY,(@LastDate),GETDATE())) As DifferenceDays/*this query will return no of days between firstdate & Current date*/