奇怪的运算符“|=”
我对编码比较陌生，无论如何，我在复制 iphone 像素技术教程时遇到了这个 if 语句，无论如何，我不太确定它在做什么，所以如果有人能为我解释一下，那就太棒了，谢谢。
for(int j = 0; j < (width * height); j++ )
{
if ( pixels[j] & 0xff000000 )
{
collisionMap[j] |= 1;
}
}
让我困惑的部分是“|=”和单个“&”符号。这是怎么回事？谢谢
i'm relatively new to coding, anyway i came across this if statement while copying a tutorial for an iphone pixel technique, anyway i'm not really sure what it's doing so if anybody could explain it for me it would be awesome thanks.
for(int j = 0; j < (width * height); j++ )
{
if ( pixels[j] & 0xff000000 )
{
collisionMap[j] |= 1;
}
}
The parts that confuse me are the '|=' and the single '&' sign. What's going on here? Thanks
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&是一个按位与。
|= 是一个按位 OR 并将值分配给
collisionMap[j]。& is a bitwise AND.
|= is a bitwise OR and assigns the value to
collisionMap[j].它们被称为 按位运算符
collisionMap[j] |= 1是相当于 CollisionMap[j] = CollisionMap[j] | 1这将确保设置了
collisionMap[j]的 LSBThey are called bitwise operators
collisionMap[j] |= 1is equivalent tocollisionMap[j] = collisionMap[j] | 1Which will make sure the LSB of
collisionMap[j]is set|=对两侧的值执行按位或（考虑优先级），将结果放入左侧变量中。因此，a |= b与a = a | 相同。 b（假设没有 C++ 运算符重载）。更具体地说，&执行按位 AND，生成一个仅包含两侧值中的位的值。|=performs a bitwise OR of the values on either side (considering precendence), putting the result into the left-side variable. So,a |= bis the same asa = a | b(assuming no C++ operator overloading). More concretely, say:&performs a bitwise AND, resulting in a value with only the bits from the values on either side.单曲&执行按位与，而
|=运算符执行按位或。The single & does a bitwise and, while the
|=operator does a bitwise or.