django-model-utils StatusModel 可以提供人类可读的状态选项吗？
我正在尝试使用 Carl Meyer 的 StatusModel 功能 ="https://bitbucket.org/carljm/django-model-utils" rel="nofollow">django-model-utils 包来创建一个具有状态字段。这是一个非常好的设计，您可以从 StatusModel 继承模型，并将 Choices 对象传递给模型上名为 STATUS 的字段，该字段会自动创建“status”和“status_changed” ' 数据库表示中的字段。
我希望我的状态字段具有与其数据库表示形式不同的人类可读值，并且 Choices 类的文档说它可以传递一个双元组，其中第一个值是选择的数据库表示形式，第二个值是人类可读的值。但是，当我尝试使用上面的 Choices 对象对 StatusModel 执行此操作时，当我在模板中使用状态字段时，我仍然可以获得数据库表示形式。
这是我的模型类的摘录：
from django.utils.translation import ugettext as _
from model_utils import Choices
from model_utils.models import StatusModel
STATUS_CHOICES = Choices(
('awaiting_approval', _('Awaiting approval')),
('returned_to_submitter', _('Returned to submitter')),
('approved', _('Approved')),
('denied', _('Denied')),
)
class Petition(StatusModel):
STATUS = STATUS_CHOICES
...
这是我的模板：
<table>
<tr>
<th>Status</th>
</tr>
{% for petition in petitions %}
<tr>
<td>{{ petition.status }}</td>
<!-- expecting "Awaiting approval" but it displays "awaiting_approval" -->
</tr>
{% endfor %}
</table>
如何让模型类返回人类可读的状态？或者 StatusModel 不支持 Choices 对象的该功能吗？
I am trying to use the StatusModel feature of Carl Meyer's awesome django-model-utils package to create a model that has a status field. It's a very nice design in which you subclass your model from StatusModel and pass a Choices object to a field on the model called STATUS, which automatically creates 'status' and 'status_changed' fields on the database representation.
I would like for my status field to have a separate human-readable value than its database representation, and the documentation for the Choices class says that it can be passed a two-tuple in which the first value is the database representation of the choice and the second is the human-readable value. But when I try doing this with my StatusModel using the above Choices object, I still get the database representation when I use the status field in a template.
Here's an excerpt of my model class:
from django.utils.translation import ugettext as _
from model_utils import Choices
from model_utils.models import StatusModel
STATUS_CHOICES = Choices(
('awaiting_approval', _('Awaiting approval')),
('returned_to_submitter', _('Returned to submitter')),
('approved', _('Approved')),
('denied', _('Denied')),
)
class Petition(StatusModel):
STATUS = STATUS_CHOICES
...
and here's my template:
<table>
<tr>
<th>Status</th>
</tr>
{% for petition in petitions %}
<tr>
<td>{{ petition.status }}</td>
<!-- expecting "Awaiting approval" but it displays "awaiting_approval" -->
</tr>
{% endfor %}
</table>
How do I get the model class to return the human readable status? Or does StatusModel not support that feature of the Choices object?
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您可以使用普通的
get_FOO_display()方法 - 在本例中{{ 请愿.get_status_display }}You can just use the normal
get_FOO_display()method - in this case{{ petition.get_status_display }}