当名称是正则表达式（日期）时的 JSON 解析

Question

如果主题标题不准确，我很抱歉，我真的不知道如何表达它（没有双关语）。 我必须使用类似于下面的结构来解析 JSON。文件中有几个这样的日期数组：每个数组都以 yyyy-MM-dd 形式的日期命名，但我不知道文件中到底有哪些日期（所以我无法通过以下方式提取数组）它的名字）。我还能怎样得到它？ 我使用 json.simple for Java 来解析文件。我不期望答案告诉我如何专门使用该库来做到这一点，但如果有人知道，那将是一个额外的好处:)

"2011-05-15":[
     {
        "promoted_content":null,
        "events":null,
        "query":"AnahiHappyBDay",
        "name":"AnahiHappyBDay"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Puerto Ricans",
        "name":"Puerto Ricans"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Epic Movie",
        "name":"Epic Movie"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Lee Soonkyu",
        "name":"Lee Soonkyu"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"MC1123",
        "name":"MC1123"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Dominique Strauss-Kahn",
        "name":"Dominique Strauss-Kahn"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"WeLoveNickJonas",
        "name":"WeLoveNickJonas"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Ripper Stefan",
        "name":"Ripper Stefan"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Luc\u00eda P\u00e9rez",
        "name":"Luc\u00eda P\u00e9rez"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"DB5K",
        "name":"DB5K"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"WeSupportYouGomez",
        "name":"WeSupportYouGomez"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"LSnoAltasHoras",
        "name":"LSnoAltasHoras"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Azerbaijan",
        "name":"Azerbaijan"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Eurovision",
        "name":"Eurovision"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Derek Boogaard",
        "name":"Derek Boogaard"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Terry Wogan",
        "name":"Terry Wogan"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"FMI",
        "name":"FMI"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"WorldLovesSwift",
        "name":"WorldLovesSwift"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"WorldWarIV",
        "name":"WorldWarIV"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Jedward",
        "name":"Jedward"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"GAGA10MILLION",
        "name":"GAGA10MILLION"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Stefan Raab",
        "name":"Stefan Raab"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Manchester United Campe\u00f3n",
        "name":"Manchester United Campe\u00f3n"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Derek Mooney",
        "name":"Derek Mooney"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Chord Overstreet",
        "name":"Chord Overstreet"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"IMF",
        "name":"IMF"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Joe Buck",
        "name":"Joe Buck"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"\u0410\u0437\u0435\u0440\u0431\u0430\u0439\u0434\u0436\u0430\u043d",
        "name":"\u0410\u0437\u0435\u0440\u0431\u0430\u0439\u0434\u0436\u0430\u043d"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"Wango Tango",
        "name":"Wango Tango"
     },
     {
        "promoted_content":null,
        "events":null,
        "query":"AlwaysRihannaNavy",
        "name":"AlwaysRihannaNavy"
     }
  ],

Answer 1

我不太确定我是否理解你的问题，但我假设你想要一个日期键列表。

使用 json.simple 解析它应该会产生一个 JSONObject，它是一个映射，因此它的 keySet() 方法将为您提供所需的内容：

JSONObject<String, Object> obj = (JSONObject<String, Object>)JSONValue.parse(s);
for (String key in obj.keySet()) {
  // do something with key
}

Answer 2

其实我不太明白你的意思...
但是，我想我有一个解决方案[使用 GSON（来自 Google 的库）]
看完你的数据后，我想我们可以创建一个类。像这样

public class Foo{
  private Date date/* or ID ?*/;
  private List<Content> contents; //a class defined blow
  /* constructors and methods */
}

public class Content{
  private String promoted_content;// Or a class? I'm not sure, because I found all of them is null
  private String events;// same as promoted_content
  private String query;
  private String name;    
  /* constructors and methods */
}

现在，使用 gson 解析您的数据。像这样

Gson gson = new Gson();//maybe you wanna read docs of gson for more detail
Foo foo = gson.fromjson(/*your data*/, Foo.class);

在这里你知道你有一个名为 Foo 的对象并且你可以获取它的值。我注意到你说也许有多个“日期”，所以我们可以创建一个包含列表的新类。