如何将一个对象的成员绑定到数据网格

发布于 2024-11-08 12:39:58 字数 417 浏览 0 评论 0原文

这是我的问题。我有一个类游戏，我想将一些成员绑定到数据网格，而不是整个对象。有什么更好的方法呢？创建另一个对象来保存信息，或者创建一个数据表？

    public class Game
    {
        public string Name {get;set; }
        public string Description {get;set;}
        public string FullPath {get;set;}

    }

    List<Game> Games = new Games { game1, game2, game3 };

dataGrid1.ItemsSource = Game;  // I don't want to do this it will bind entire object.

原文

Here is my problem. I have a class game, and i would like to bind some of the members to the datagrid, not entire object. What is better way to do it? Create another object to hold infomation, or create a datatable?

    public class Game
    {
        public string Name {get;set; }
        public string Description {get;set;}
        public string FullPath {get;set;}

    }

    List<Game> Games = new Games { game1, game2, game3 };

dataGrid1.ItemsSource = Game;  // I don't want to do this it will bind entire object.

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两仪 2024-11-15 12:39:58

您仍然可以绑定整个对象、关闭列的自动生成以及手动创建和绑定列。

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晨光如昨 2024-11-15 12:39:58

为什么不创建另一个继承游戏类的类。以游戏2为例。然后创建构造函数以仅设置您在游戏一中想要/需要的内容。使用 linq 你可以过滤掉它。

var newData = from item in game
              select new game 2
              {
                  object1 = item.object1,
                  object2 = item.object2
              };

然后您可以将 newData 设置为数据源。请原谅我的任何语法错误。如果你查一下 linq，这是一个非常简单的概念。您甚至不需要继承游戏类。您可以使用所需的信息创建一个名为游戏 2 的独立类。

Why don't you create another class that inherits the game class. Game2 for example. Then create the constructor to only set what you want/need from game one. Using linq you can filter this out.

var newData = from item in game
              select new game 2
              {
                  object1 = item.object1,
                  object2 = item.object2
              };

Then you can set newData as the datasource. Forgive me for any syntax errors. If you look up linq this is a pretty easy concept. You don't need to even inherit the game class. You can create a independent class called game 2 with the info you need.

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