jQuery 在 $(document).ready(function() { 中运行函数

发布于 2024-11-08 07:36:52 字数 391 浏览 0 评论 0原文

我在这里做错了什么?为什么 writeQuestions 不运行在负载上(而不是 onclick..)?

$(document).ready(function() {

$.getJSON("JavaScript/questions.json", function(data) {questions = data;});
    $("#start").one("click" , writeQuestions);
    writeQuestions();

 });

.one() 行在我的代码中被注释掉)

当我这样做时:window.onload=writeQuestions; 它工作正常..

What am I doing wrong here? why writeQuestions doesn't run on-load (not onclick..)?

$(document).ready(function() {

$.getJSON("JavaScript/questions.json", function(data) {questions = data;});
    $("#start").one("click" , writeQuestions);
    writeQuestions();

 });

(the .one() line is commented out in my code)

When i do this:window.onload=writeQuestions; it works fine..

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(3

回忆那么伤 2024-11-15 07:36:52

writeQuestions() 在返回 JSON 结果之前运行。将函数调用放在回调函数中。

$(document).ready(function() {  
     $.getJSON("JavaScript/questions.json", 
          function(data) { questions = data; writeQuestions(); }
     ); 
}); 

另外,我建议更新 writeQuestions() 函数以接受参数,并以这种方式传递问题。我很惊讶它竟然有效,因为存在可变范围问题。

writeQuestions() is running before the JSON result is returned. Put the function call in the callback function.

$(document).ready(function() {  
     $.getJSON("JavaScript/questions.json", 
          function(data) { questions = data; writeQuestions(); }
     ); 
}); 

Also, I would recommend updating the writeQuestions() function to accept a parameter, and passing the questions that way. I am surprised it ever worked, since there are variable scope issues.

草莓酥 2024-11-15 07:36:52

您是否尝试过...

$.getJSON("JavaScript/questions.json", function(data) {
    questions = data;
    writeQuestions();
});

在您的示例中,将在 getJSON 调用返回之前调用 writeQuestions

编辑正如 Fosco 在他的回答中指出的那样,您在此处将 questions 声明为全局变量,因为您不使用 var 关键字。这可能有效,但这不是好的做法,而且容易出现错误。最好重写为:

$.getJSON("JavaScript/questions.json", function(data) {
    writeQuestions(data);
});

Have you tried...

$.getJSON("JavaScript/questions.json", function(data) {
    questions = data;
    writeQuestions();
});

In your example writeQuestions will be called before the getJSON call has returned.

Edit as Fosco pointed out in his answer, you are declaring questions as a global variable here as you do not use the var keyword. This might work but it is not good practice and is bug prone. It would be better to re-write as:

$.getJSON("JavaScript/questions.json", function(data) {
    writeQuestions(data);
});
耳根太软 2024-11-15 07:36:52

您的问题是否已加载到 .getJSON() 中?
如果是这样,请尝试输入成功

$.getJSON("JavaScript/questions.json", function(data) {
    questions = data;
}).success(function() {writeQuestions();)

are your questions loaded in the .getJSON()?
IF so, try putting in a success

$.getJSON("JavaScript/questions.json", function(data) {
    questions = data;
}).success(function() {writeQuestions();)
~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文