there is not straight forward method to add two vectors which are in [magnitude,argument] form. They need to be converted into Cartesian co-ordinates before adding them up and finding mean. so, unfortunately the mean isn't
The mean is usually described as the arithemtic mean of 2 or more values (see Mean). Based on the definition I would suggest to add all the available vectors and divide the sum vector by the amount of vectors given.
For your example the mean would be calculated like this
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各自的笛卡尔向量为
(Amp1 * cos theta1, Amp1 * sin theta1) 和
(Amp2 * cos theta2, Amp2 * sin theta 2)。
现在添加各自的坐标并除以向量的数量 (2) 以获得（算术）平均值。
The respective Cartesian vectors are
(Amp1 * cos theta1, Amp1 * sin theta1) and
(Amp2 * cos theta2, Amp2 * sin theta 2).
Now add the respective coordinates and divide by the number of vectors (2) to get the (arithmetic) mean.
没有直接的方法可以将两个 [magnitude,argument] 形式的向量相加。在将它们相加并求平均值之前，需要将它们转换为笛卡尔坐标。
所以，不幸的是平均值不是
there is not straight forward method to add two vectors which are in [magnitude,argument] form. They need to be converted into Cartesian co-ordinates before adding them up and finding mean.
so, unfortunately the mean isn't
平均值通常被描述为 2 个或多个值的算术平均值（请参阅平均值）。根据定义，我建议将所有可用向量相加，并将总向量除以给定向量的数量。
对于您的示例，平均值将这样计算
并且通常只有一个平均值。
The mean is usually described as the arithemtic mean of 2 or more values (see Mean). Based on the definition I would suggest to add all the available vectors and divide the sum vector by the amount of vectors given.
For your example the mean would be calculated like this
And there is usually only one mean value.