Inkscape:如何使用以毫米为单位而不是百分比的移位来创建平铺克隆
我正在尝试在 Inkscape 中创建一个三角形网格。我将创建一条斜线,然后沿某个方向克隆它以获得栅栏,然后以 60 度和 120 度克隆栅栏以获得网格,例如,步长为 5 毫米。
问题在于,创建克隆是通过以原始对象尺寸的百分比表示的偏移来指定的。由于原始线是倾斜的,因此其尺寸以丑陋的毫米分数表示。因此,为了指定对应于 5 毫米步长的百分比变化,我必须计算更丑陋的分数。百分比的微小误差可能会导致累积位移误差,从而可能导致远处的克隆不在常规 5 毫米网格上。
如何使用毫米而不是百分比指定克隆的位移?
I'm trying to create a triangular grid in Inkscape. I'm going to create a slanted line then clone it along a direction to obtain a fence, then clone the fence at 60 and 120 degrees to obtain a grid at, for example, 5-mm steps.
The problem is that creating a clone is specified by shifts expressed in percentages of the original object's dimensions. Since the original line is slanted, it's dimensions are expressed in ugly fractions of mm. So, to specify a shift in percent that would correspond to a 5-mm step, I have to calculate even uglier fraction. A small inaccuracy of the percentage can lead to the cumulative shift error, which may result in distant clones not being on the regular 5-mm grid.
How can I specify the shift of the clones using millimeters, not percent?
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似乎这个问题有一个自由软件的典型答案:这个问题在 2005 年就被强调了,并且在近六年的时间里还没有得到解决(或者实际上实现) - 请参阅 bugtracker: https://bugs.launchpad.net/inkscape/+bug/170835
It seems that this question has an answer typical to free software: this issue has been highlighted in 2005, and hasn't been fixed (or, actually, implemented) for almost six years - see the bugtracker: https://bugs.launchpad.net/inkscape/+bug/170835