MySQL - 当嵌套选择使用该表时如何从表中删除？

发布于 2024-11-08 02:19:43 字数 448 浏览 0 评论 0原文

我正在尝试做这样的事情：

DELETE FROM table_1
WHERE  table_1.id IN (SELECT table_1.id
                      FROM   table_1,
                             table_2,
                             table_3
                      WHERE  table_1.id = table_2.table_1_id
                      AND    table_2.id = table_3.table_2_id
                      AND    table_3.id = 5)

似乎 MySQL 不允许我在嵌套 SELECT 中拥有 table_1 。建议？

原文

I'm trying to do something like this:

DELETE FROM table_1
WHERE  table_1.id IN (SELECT table_1.id
                      FROM   table_1,
                             table_2,
                             table_3
                      WHERE  table_1.id = table_2.table_1_id
                      AND    table_2.id = table_3.table_2_id
                      AND    table_3.id = 5)

Seems like MySQL won't let me have table_1 in the nested SELECT. Suggestions?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

小帐篷 2024-11-15 02:19:43

您可能会收到此错误：

ERROR 1093 (HY000): You can't specify target table 'table_1' for update in FROM clause.

您应该能够使用 MySQL 的多表 DELETE 语法：

DELETE table_1.*
FROM   table_1,
       table_2,
       table_3
WHERE  table_1.id = table_2.table_1_id
AND    table_2.id = table_3.table_2_id
AND    table_3.id = 5

上面的查询应该可以工作，但作为一般规则，我建议使用 ANSI JOIN 语法：

DELETE table_1.*
FROM   table_1
INNER JOIN table_2 on table_2.table_1_id = table_1.id
INNER JOIN table_3 on table_3.table_2_id = table_2.id
WHERE table_3.id = 5

You're probably getting this error:

ERROR 1093 (HY000): You can't specify target table 'table_1' for update in FROM clause.

You should be able to do this using MySQL's multiple-table DELETE syntax instead:

DELETE table_1.*
FROM   table_1,
       table_2,
       table_3
WHERE  table_1.id = table_2.table_1_id
AND    table_2.id = table_3.table_2_id
AND    table_3.id = 5

The above query should work, but as a general rule I would recommend using ANSI JOIN syntax instead:

DELETE table_1.*
FROM   table_1
INNER JOIN table_2 on table_2.table_1_id = table_1.id
INNER JOIN table_3 on table_3.table_2_id = table_2.id
WHERE table_3.id = 5

回复收藏 0 原文

~没有更多了~