将大于 255 的数字转换为字节变量

发布于 2024-11-08 01:56:57 字数 370 浏览 1 评论 0原文

我理解字节的概念和声明变量以节省处理空间。我知道一个字节可以存储的最大值是 255。

我似乎无法解决当前的问题，希望有人能够教育我并帮助我解决这个问题。我没有太多使用字节操作的经验。

我收到了一个需要更新的项目，并被告知将数据传递到我的项目的服务将开始使用 2 字节来传输 ID，而不是之前的 1 字节，因为它们的参数已经增长。

该变量的当前声明是：

Dim bytvariable As Byte = 0

接受 2 字节值的新声明是什么？

其次，我如何才能将 2 字节值转换为整数？

例如，他们向我传递了这个值：0x138，它应该显示为 312。

提前谢谢您。

原文

I understand the concept of bytes and declaring variables to save on processing space. I understand that the max value that can be stored in a byte is 255.

I cannot seem to wrap my head around my current issue and was hoping that someone would be able to educate me and help me solve this problem. I don't have much experience working with byte manipulation.

I was given a project to update and was told that the service that is passing data to my project would start using 2bytes to transfer the ID rather than the 1 byte previously as their parameters have grown.

The current declaration for the variable is:

Dim bytvariable As Byte = 0

What is the new declaration to accept a 2 byte value?

Secondly, how would I be able to convert that 2 byte value into an integer number?

Example, they are passing me this value: 0x138 and it is supposed to come out as 312.

Thank you in advance.

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稚气少女 2024-11-15 01:56:57

以下是“原语”的摘要 " .NET 中的数据类型及其大小。

是的，Int16 可能就是您想要的。

通常，您会从流中读取二进制数据，或者从字节数组中获取它。
要将这些源转换为 Int16，您可以这样做：

在 C# 中：

byte[] block = new byte[128];
mystream.Read(block, 0, block.Length);
int i = 0;
Int16 value = (Int16)(block[i++] + block[i++] * 256);

在 VB.NET 中，它将是：（

Dim block as New Byte(128)
stream.Read(block, 0, block.Length)
Dim i as Int16 = 0
Dim value As Short = CShort((block(i) + (buffer(i+1) * &H100)))
i = i + 2

我认为）

Here's a summary of the "primitive" datatypes in .NET, and their sizes.

Yes, an Int16 is probably what you want.

Often you'd be reading the binary data from a stream, or getting it from an array of bytes.
To convert from those sources into an Int16, you can do this:

in C#:

byte[] block = new byte[128];
mystream.Read(block, 0, block.Length);
int i = 0;
Int16 value = (Int16)(block[i++] + block[i++] * 256);

In VB.NET, it would be:

Dim block as New Byte(128)
stream.Read(block, 0, block.Length)
Dim i as Int16 = 0
Dim value As Short = CShort((block(i) + (buffer(i+1) * &H100)))
i = i + 2

(I think)

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追星践月 2024-11-15 01:56:57

从我的头脑中，我建议如果你坚持这样做（而不是仅仅传递一个整数），你可以使用一个字节数组，第一个索引保存第一个数字，第二个索引保存第二个数字。字节[0] = 123，字节[1] = 255；

然后将它们组合成一个字符串 ex。字符串连接数 = byte[0].ToString() + byte[1].ToString();然后解析它。 int ID = Int32.Parse(concatenatedNumber);

示例是 C# 语言，但我认为您应该明白了。不过，我肯定宁愿将其作为整数传递。

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旧故 2024-11-15 01:56:57

你可以试试这个：

Dim bytvariable As Byte(0 To 1)

bytvariable(0) = ' Get the first byte however they are sending it
bytvariable(1) = ' Get the second byte however they are sending it
Dim value As Int16 = BitConverter.ToInt16(buffer, 0);

You could try this:

Dim bytvariable As Byte(0 To 1)

bytvariable(0) = ' Get the first byte however they are sending it
bytvariable(1) = ' Get the second byte however they are sending it
Dim value As Int16 = BitConverter.ToInt16(buffer, 0);

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