我可以改变Python中对象的 name 属性吗？

发布于 2024-11-08 00:17:15 字数 321 浏览 0 评论 0原文

更改对象的 __name__ 属性值是否正确，如下例所示：

>>>
>>> def f(): pass
...
>>> f.__name__
'f'
>>> b = f
>>> b.__name__
'f'
>>> b.__name__ = 'b'
>>> b
<function b at 0x0000000002379278>
>>> b.__name__
'b'
>>>

原文

Is it correct to change the value of __name__ atribute of object like in the following example:

>>>
>>> def f(): pass
...
>>> f.__name__
'f'
>>> b = f
>>> b.__name__
'f'
>>> b.__name__ = 'b'
>>> b
<function b at 0x0000000002379278>
>>> b.__name__
'b'
>>>

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浴红衣 2024-11-15 00:17:15

更改函数的名称并不会使新名称可调用：

>>> def f(): print 'called %s'%(f.__name__)
...
>>> f()
called f
>>> f.__name__ = 'b'
>>> f()
called b
>>> b()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name 'b' is not defined

您必须定义 b 才能调用它。正如您所看到的，简单地分配 b=f 并不会定义新函数。

Changing a function's name doesn't make the new name callable:

>>> def f(): print 'called %s'%(f.__name__)
...
>>> f()
called f
>>> f.__name__ = 'b'
>>> f()
called b
>>> b()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name 'b' is not defined

You'd have to define b in order to call it. And as you saw, simply assigning b=f doesn't define a new function.

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我喜欢麦丽素 2024-11-15 00:17:15

是的，您可以更改__name__。我有时会更改装饰器实例的 __name__ 以反映它正在装饰的函数，例如，

class CallTrace:

...

def __init__(self, f):
    self.f = f
    self.__name__ = f.__name__ + ' (CallTraced)'

我并不是断言这是一个好的做法，但它过去帮助我调试代码。这个想法是，如果您装饰一个函数 fn，然后在提示符下键入 fn.__name__，您可以立即看到它已被装饰。

Yes, you can change __name__. I sometimes change the __name__ of a decorator instance to reflect the function it's decorating, e.g.

class CallTrace:

...

def __init__(self, f):
    self.f = f
    self.__name__ = f.__name__ + ' (CallTraced)'

I'm not asserting this is good practice, but it has helped me debug code in the past. The idea is if you decorate a function fn, then type fn.__name__ at the prompt, you can see immediately that it's decorated.

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