Python，单步执行文件夹（以运行脚本）

发布于 2024-11-07 23:46:50 字数 596 浏览 0 评论 0原文

由于我不熟悉Python，所以我想我应该来这里。

无论如何，我有几个文件夹（假设有 20 个文件夹）每个文件夹内有更多文件夹（假设每个文件夹有 5 个）在这些文件夹中的每个文件夹中都有另一个文件夹，其中有一个我需要运行的脚本。

脚本以相同的方式运行 'ie':sh script.sh

基本上我需要为每个文件夹运行这个脚本，问题是我不知道如何进入每个文件夹（有脚本），这是 4 个级别从原始文件夹下来。

因此，总共有大约 120 个脚本需要以相同的方式运行（该脚本还返回一个数字，例如（1 表示成功，0 表示失败），我需要记录这些数字（应该不难弄清楚）

最好的方法是什么？我想我可以弄清楚检查结果，但老实说我不太熟悉Python。

为了让大家清楚，文件夹结构是这样的：
顶级（20 个左右文件夹）
 --> 下面 1 个（大约 5 个文件夹）
 ----->这5个文件夹之一下面的1（仅包含1个文件夹）
 --------->1 在该文件夹下（这里是脚本所在的位置）

不要问我为什么文件夹是这样构造的......哈哈。这最好在 python 2 中完成。

原文

Since Im unfamiliar with Python I thought i'd come here.

Anyways I have several Folders (lets say 20 folders)
Within each folder is more folders (lets say 5 per)
and within EACH one of these folders is another folder, and within THAT is a script I need to run.

The script is ran the same way 'ie':sh script.sh

Basically I need to run this script for each of these folders, problem is I have no clue how to step into each folder (that has the script) which is 4 levels down from the original folder.

So there are a total of like 120 scripts that need to be ran the same way (this script also returns a number for instance (1 for success, 0 for failure) that I need to record (shouldn't be too hard to figure out)

What would be the best way to go about this? The Checking results I think I can figure out, but stepping through all these subfolders Im honestly not well versed in python to know about.

Just so everyones clear the folder structure is like this:
Top Level (20 or so folders)
 -->1 Below (5 or so Folders)
 ----->1 below one of these 5 folders (only 1 folder is contained)
 --------->1 below that one folder (here is where the script resides)

Don't ask me why the folders are structured this way.....lol. This would be done in python 2 preferably.

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何时共饮酒 2024-11-14 23:46:50

import glob,subprocess
for script in glob.glob('*/*/*/*.sh'):
   s = subprocess.Popen([script], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
   stdoutdata,stderrdata = s.communicate()
   returncode = s.returncode
   # Do something with stdoutdata, returncode etc. here

import glob,subprocess
for script in glob.glob('*/*/*/*.sh'):
   s = subprocess.Popen([script], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
   stdoutdata,stderrdata = s.communicate()
   returncode = s.returncode
   # Do something with stdoutdata, returncode etc. here

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怪我闹别瞎闹 2024-11-14 23:46:50

有点矫枉过正，但它应该有效：

import os

root = '/foo/'

for directory, subdirectories, files in os.walk(root):
  for file in files:
     if os.path.splitext(file)[-1].lower() == '.sh':
       os.system('sh ' + os.path.join(directory, file))

A bit overkill, but it should work:

import os

root = '/foo/'

for directory, subdirectories, files in os.walk(root):
  for file in files:
     if os.path.splitext(file)[-1].lower() == '.sh':
       os.system('sh ' + os.path.join(directory, file))

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~没有更多了~