C++ - 如何从类的构造函数中初始化单独类的构造函数？
基本上我想要实现的目标是在genicAlgorithm类中创建deltaKinematics类的本地（私有）实例
在genicAlgorithm.h中> 我有的文件：
class DeltaKinematics; //class is defined in separate linked files
class GeneticAlgorithm {
//private
DeltaKinematics deltaRobot;
public:
GeneticAlgorithm(); //constructor
};
这一切都很好，但是当我去声明 GeneticAlgorithm 构造函数时，我无法弄清楚如何构造 DeltaKinematics 的实例，
这是genicAlgorithm.cpp 构造函数：
GeneticAlgorithm::GeneticAlgorithm(){ //The error given on this line is "constructor for 'GeneticAlgorithm' must explicitly initialize the member 'deltaRobot' which does not have a default constructor"
DeltaKinematics deltaRobot(100); //this clearly isn't doing the trick
cout << "Genetic Algorithmic search class initiated \n";
}
如何初始化该本地实例？
Basically what I am trying to achieve is to create a local (and private) instance of the class deltaKinematics in the class geneticAlgorithm
In the geneticAlgorithm.h file I have:
class DeltaKinematics; //class is defined in separate linked files
class GeneticAlgorithm {
//private
DeltaKinematics deltaRobot;
public:
GeneticAlgorithm(); //constructor
};
This is all fine, but when I go to declare the GeneticAlgorithm constructor, I can't work out how to construct the instance of DeltaKinematics
This is the geneticAlgorithm.cpp constructor:
GeneticAlgorithm::GeneticAlgorithm(){ //The error given on this line is "constructor for 'GeneticAlgorithm' must explicitly initialize the member 'deltaRobot' which does not have a default constructor"
DeltaKinematics deltaRobot(100); //this clearly isn't doing the trick
cout << "Genetic Algorithmic search class initiated \n";
}
How do I go about initializing that local instance?
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成员初始值设定项列表：
Member initializer list:
请注意构造函数名称后面的
:：它是类的成员数据变量初始化序列的开始。它们显示为对其构造函数的调用，带有您要传递的参数，并且应采用与声明的顺序相同的顺序。Note the
:after the constructor name: it is the beginning of the initialization sequence for the member data variables of the class. They appear as calls to their constructors, with the parameters you want to pass, and should be in the same order they're declared.