文件重命名/删除

发布于 2024-11-07 18:49:14 字数 980 浏览 1 评论 0原文

我有一些像这样的文件 -

*.sss 和 *_passive.sss

如果我有一个名为 blah1.sss 和 blah1_passive.sss 的文件，我想删除 blah1.sss 并重命名 blah1_passive.sss。但是，如果我没有 blah1_passive.sss，我想记录文件名并保留 blah1.sss。

我能够找到所有 *_passive.sss 文件，但我想知道可以将 *_passive.sss 重命名为 *.sss 的 awk/sed 等命令。

编辑：现在我有这个，但 os.rename 不会覆盖文件，但我需要它来覆盖。

import os, fnmatch

def locate(pattern, root=os.curdir):

    #ignore directories- uncomment to make ignore work
    #ignored = ["0201", "0306"]
  for path, dirs, files in os.walk(os.path.abspath(root)):
         #for dir in ignored:                  # if dir in dirs:                        #dirs.remove(dir)
    for filename in fnmatch.filter(files, pattern):
       yield os.path.join(path, filename)



for filename in locate("*_passive.sss"):
               #found the files that i want to rename, but os.rename() refuses to overwrite !! 
    newfilename=filename.rstrip("_passive.sss") + ".sss"
    os.rename(filename,newfilename)

原文

I have a few files like this-

*.sss and *_passive.sss

If I have a file called blah1.sss and blah1_passive.sss, i want to get rid of blah1.sss and rename blah1_passive.sss. However, if I don't have blah1_passive.sss I want to log the filename and keep blah1.sss.

I was able to locate all the *_passive.sss files but I would like to know the awk/sed etc command that could rename the *_passive.sss to *.sss.

Edit: Right now i have this but os.rename does not overwrite files, i need it to overwrite though.

import os, fnmatch

def locate(pattern, root=os.curdir):

    #ignore directories- uncomment to make ignore work
    #ignored = ["0201", "0306"]
  for path, dirs, files in os.walk(os.path.abspath(root)):
         #for dir in ignored:                  # if dir in dirs:                        #dirs.remove(dir)
    for filename in fnmatch.filter(files, pattern):
       yield os.path.join(path, filename)



for filename in locate("*_passive.sss"):
               #found the files that i want to rename, but os.rename() refuses to overwrite !! 
    newfilename=filename.rstrip("_passive.sss") + ".sss"
    os.rename(filename,newfilename)

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贪恋 2024-11-14 18:49:14

在 Unix 中，您可以在 Bourne shell 中使用以下命令（即 sh/bash）：

for f in *_passive.sss; do mv -v $f `basename $f _passive.sss`.sss; done

In Unix you can use the following command in a Bourne shell (i.e. sh/bash):

for f in *_passive.sss; do mv -v $f `basename $f _passive.sss`.sss; done

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那支青花 2024-11-14 18:49:14

这个 shell 脚本应该可以解决这个问题：

while read f; do
    fp="`echo "$f" | sed -nr 's|(.*)(\.sss)|\1_passive\2| p'`"
    if [ -f "$fp" ]; then mv "$fp" "$f"
    else  echo "file $fp missing" >> missing.log
    fi
done<<<"`ls -1 *.sss | grep -v _passive.sss`"

还会向 missing.log 报告丢失的 _passive 文件

This shell script shoul do the trick:

while read f; do
    fp="`echo "$f" | sed -nr 's|(.*)(\.sss)|\1_passive\2| p'`"
    if [ -f "$fp" ]; then mv "$fp" "$f"
    else  echo "file $fp missing" >> missing.log
    fi
done<<<"`ls -1 *.sss | grep -v _passive.sss`"

also will report missing _passive files to missing.log

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鲸落 2024-11-14 18:49:14

这是一个Python解决方案：

import os
from glob import glob

# Write out test files.
with open('foo.sss', 'w'):  pass
with open('foo_passive.sss', 'w'):  pass
with open('bar.sss', 'w'):  pass

# Rename files.
files = glob('*.sss')
for filename in files:
  if filename.endswith('_passive.sss'):  continue
  passive_fname = filename.split('.sss')[0] + '_passive.sss'
  if passive_fname in files:
    os.remove(filename)
    os.rename(passive_fname, filename)
  else:
    print 'no passive: ', filename

Here's a python solution:

import os
from glob import glob

# Write out test files.
with open('foo.sss', 'w'):  pass
with open('foo_passive.sss', 'w'):  pass
with open('bar.sss', 'w'):  pass

# Rename files.
files = glob('*.sss')
for filename in files:
  if filename.endswith('_passive.sss'):  continue
  passive_fname = filename.split('.sss')[0] + '_passive.sss'
  if passive_fname in files:
    os.remove(filename)
    os.rename(passive_fname, filename)
  else:
    print 'no passive: ', filename

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