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如何按比例（尊重长宽比）缩放矩形？

发布于 2024-11-07 18:45:27 字数 162 浏览 0 评论 0原文

我试图简单地获取给定的 x 和 y 框并将其放大，方法是设置 x 并查找 y，反之亦然。这个公式如何用 Python 表达（为了可读性）。我试图将这个盒子放入一个较大的盒子内，以便内盒始终适合较大的盒子。

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还在原地等你 2024-11-14 18:45:27

注意：我并不真正使用 Python，所以这是伪代码。

您需要的是两个框的相对纵横比，因为这决定了哪个新轴必须与新框的大小相同：

r_old = old_w / old_h
r_new = new_w / new_h

if (r_old > r_new) then
   w = new_w              // width of mapped rect
   h = w / r_old          // height of mapped rect
   x = 0                  // x-coord of mapped rect
   y = (new_h - h) / 2    // y-coord of centered mapped rect
else
   h = new_h
   w = h * r_old
   y = 0
   x = (new_w - w) / 2
endif

NB: I don't really do Python, so this is pseudocode.

What you need is the relative aspect ratios of the two boxes, since that determines which of the new axes must be the same size as the new box:

r_old = old_w / old_h
r_new = new_w / new_h

if (r_old > r_new) then
   w = new_w              // width of mapped rect
   h = w / r_old          // height of mapped rect
   x = 0                  // x-coord of mapped rect
   y = (new_h - h) / 2    // y-coord of centered mapped rect
else
   h = new_h
   w = h * r_old
   y = 0
   x = (new_w - w) / 2
endif

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要走就滚别墨迹 2024-11-14 18:45:27

new_y = (float(new_x) / x) * y

或

new_x = (float(new_y) / y) * x

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淡墨 2024-11-14 18:45:27

>>> import fractions
>>> x, y = 10, 10
>>> fix_rat = fractions.Fraction(x, y)
>>> fix_rat
Fraction(1, 1)
>>> x = 8
>>> if fractions.Fraction(x, y) != fix_rat:
    y = x / fix_rat #well instead of y you should put the last one that has been changed
                    #but this is just an example


>>> y
Fraction(8, 1)
>>>

>>> import fractions
>>> x, y = 10, 10
>>> fix_rat = fractions.Fraction(x, y)
>>> fix_rat
Fraction(1, 1)
>>> x = 8
>>> if fractions.Fraction(x, y) != fix_rat:
    y = x / fix_rat #well instead of y you should put the last one that has been changed
                    #but this is just an example


>>> y
Fraction(8, 1)
>>>

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~没有更多了~