matplotlib 图形在 show() 和 savefig() 之间消失

发布于 2024-11-07 12:59:05 字数 633 浏览 0 评论 0原文

我在字典中保存了一组对数字的引用，以便以后需要时可以保存它们。如果调用 show() 命令并先查看它们，我很担心保存的数字是空白的。由于 show() 命令会阻塞，并且我没有使用类似间谍程序的解释器，因此我必须在到达 savefig() 之前关闭数字。

figures['myfig_1'] = figure()
...
figures['myfig_n'] = figure()
...

#show() #disabling this makes the problem go away
print "Saving:"
for fig in figures:
   figure(figures[fig].number)
   savefig(fig)
   print "Figure " + str(figures[fig].number) + ": " + fig

这里的 print 语句有给我指示字典仍然完好无损，我认为这意味着我没有丢失图形引用（它们仍然在 .number 属性中返回有意义的数字。）

我注意到的另一个变化是当我在类中做了类似的事情，将字典存储为成员并将存储和保存函数划分为它们自己的方法时，这种情况不会发生。我关闭数字或存储数据的方式是否导致数字丢失数据？

原文

I've kept a set of references to figures in a dictionary so that I could save them later if desired. I am troubled that the saved figures are blank if invoke a show() command and look at them first. Since the show() command blocks and I am not using a spyder-like interpreter, I have to close the figures before I get to savefig()

figures['myfig_1'] = figure()
...
figures['myfig_n'] = figure()
...

#show() #disabling this makes the problem go away
print "Saving:"
for fig in figures:
   figure(figures[fig].number)
   savefig(fig)
   print "Figure " + str(figures[fig].number) + ": " + fig

The print statement here has given me the indication that the dictionary is still intact, which I think means that I have not lost the figure references (they are still returning meaningful numbers in their .number attribute.)

Another twist I have noticed is that when I have done a similar thing in a class, storing the dictionary as a member and dividing the store and save functions into their own methods, this does not happen. Is there something about the way I am closing the figures or storing the data which is making the figures loose their data?

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烟若柳尘 2024-11-14 12:59:05

一般来说，在这种情况下，不要使用 matplotlib 的交互式 matlab-ish 状态机接口。它适用于交互式使用。

您试图使一个图形“活跃”，并创建一个新图形。如果您只是保留返回的图形和/或轴对象并直接使用它们，那么哪个图形处于活动状态并不重要。（另外，不要使用通配符导入！当您维护代码时，您将会后悔！）

只需执行以下操作：

import matplotlib.pyplot as plt
figures = {}

figures['a'] = plt.figure()
ax = figures['a'].add_subplot(111)
ax.plot(range(10), 'ro-')

figures['b'] = plt.figure()
ax = figures['b'].add_subplot(111)
ax.plot(range(10), 'bo-')

plt.show()

for name, fig in figures.iteritems():
    fig.savefig('figure-%s.png' % name)

Generally speaking, in cases like this don't use the interactive matlab-ish state machine interface to matplotlib. It's meant for interactive use.

You're trying to make a figure "active", and creating a new figure instead. It doesn't matter which figure is active, if you just retain the returned figure and/or axis objects and use them directly. (Also, don't use wildcard imports! You will regret it at some later point when you're maintaining your code!)

Just do something like this:

import matplotlib.pyplot as plt
figures = {}

figures['a'] = plt.figure()
ax = figures['a'].add_subplot(111)
ax.plot(range(10), 'ro-')

figures['b'] = plt.figure()
ax = figures['b'].add_subplot(111)
ax.plot(range(10), 'bo-')

plt.show()

for name, fig in figures.iteritems():
    fig.savefig('figure-%s.png' % name)

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