如何从 Twitter JSON 数组中提取值
我正在创建一个 php 脚本来检查是否有人在 Twitter 上关注我，并且我正在使用 REST API 方法：友谊显示方法 并使用 themattHarris tmhOAuth 库进行 OAuth。
我使用以下代码发出请求：
$code=$tmhOAuth->request('GET', $tmhOAuth->url('friendships/show'), array( 'target_screen_name' => 'bob' ));
if ($code==200){ $code = json_decode($tmhOAuth->response['response'], true); }
请求成功并返回类似 json 输出，如 apiwiki 页面所示：
{"relationship": { "source": { "id": 123, "screen_name": "bob", "following": true, "followed_by": false, "notifications_enabled": false }, "target": { "id": 456, "screen_name": "jack", "following": false, "followed_by": true, "notifications_enabled": null } } }
我的问题
如何从返回的数组中提取以下值？
"id": 456,
I am creating a php script to check if a person is following me on Twitter and I am using the REST API Method: friendships show method and using themattHarris tmhOAuth library for OAuth.
I am making the request using the following code:
$code=$tmhOAuth->request('GET', $tmhOAuth->url('friendships/show'), array( 'target_screen_name' => 'bob' ));
if ($code==200){ $code = json_decode($tmhOAuth->response['response'], true); }
The request is successful and returns similar json output as shown on the apiwiki page:
{"relationship": { "source": { "id": 123, "screen_name": "bob", "following": true, "followed_by": false, "notifications_enabled": false }, "target": { "id": 456, "screen_name": "jack", "following": false, "followed_by": true, "notifications_enabled": null } } }
MY QUESTION
How do I extract the following value from the array returned?
"id": 456,
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评论（3）
经过
json_decode编辑后，它只是一个 PHP 数组，对吧？或者
It's just a PHP array after it's been
json_decodeed, right?or
看一下示例：http://codepad.org/KMEP5wPW
Look at example: http://codepad.org/KMEP5wPW
您已经应用了
json_decode()，因此您正在讨论的值应该可以通过以下代码访问：因为仅当
$code = 时您才覆盖，您必须假设$code= 200$code可能与json_decode()的结果不同。You already applied
json_decode(), so the value you are talking about should be accessible by the following code:Because you have overwritten
$codeonly when$code == 200, you have to assume$codemay be something different than result fromjson_decode().