Apache POI XSSF 读取 Excel 文件

Question

我只是有一个关于如何使用 Apache 的 XSSF 格式读取 xlsx 文件的快速问题。

现在我的代码如下所示：

InputStream fs = new FileInputStream(filename);   // (1)
XSSFWorkbook wb = new XSSFWorkbook(fs);           // (2)
XSSFSheet sheet = wb.getSheetAt(0);               // (3)

...导入了所有相关内容。我的问题是，当我点击运行时，它卡在第 (2) 行，几乎陷入无限循环。 filename 只是一个字符串。

如果有人能给我一些关于如何解决这个问题的示例代码，我将非常感激。我现在想要的只是从 xlsx 文件中读取单个单元格；我对 xls 文件使用 HSSF，没有任何问题。

感谢您的帮助， 安德鲁

Answer 1

我相信这会回答您的问题： http://poi.apache.org/ Spreadsheet/quick-guide.html#ReadWriteWorkbook

简而言之，您的代码应如下所示：

InputStream inp = new FileInputStream("workbook.xlsx");
Workbook wb = WorkbookFactory.create(inp);
Sheet sheet = wb.getSheetAt(0);
Row row = sheet.getRow(2);
Cell cell = row.getCell(3);

Answer 2

InputStream inp = null;
        try {
            inp = new FileInputStream("E:/sample_poi.xls");

            Workbook wb = WorkbookFactory.create(inp);
            Sheet sheet = wb.getSheetAt(0);
            Header header = sheet.getHeader();

            int rowsCount = sheet.getLastRowNum();
            System.out.println("Total Number of Rows: " + (rowsCount + 1));
            for (int i = 0; i <= rowsCount; i++) {
                Row row = sheet.getRow(i);
                int colCounts = row.getLastCellNum();
                System.out.println("Total Number of Cols: " + colCounts);
                for (int j = 0; j < colCounts; j++) {
                    Cell cell = row.getCell(j);
                    System.out.println("[" + i + "," + j + "]=" + cell.getStringCellValue());
                }
            }

        } catch (Exception ex) {
            java.util.logging.Logger.getLogger(FieldController.class.getName()).log(Level.SEVERE, null, ex);
        } finally {
            try {
                inp.close();
            } catch (IOException ex) {
                java.util.logging.Logger.getLogger(FieldController.class.getName()).log(Level.SEVERE, null, ex);
            }
        }

Answer 3

为什么要将文件分解为输入流？ XSSFWorkbook 有一个构造函数，它仅将路径作为字符串。只需对字符串的路径进行硬编码即可。创建工作簿后，您可以从中创建 XSSFSheets。然后是 XSSFCells，它最终将允许您读取单个单元格的内容（单元格本质上基于 x,y 位置）

Answer 4

您可以尝试以下操作。

private static void readXLSX(String path) throws IOException {
    File myFile = new File(path);
    FileInputStream fis = new FileInputStream(myFile);

    // Finds the workbook instance for XLSX file
    XSSFWorkbook myWorkBook = new XSSFWorkbook (fis);

    // Return first sheet from the XLSX workbook
    XSSFSheet mySheet = myWorkBook.getSheetAt(0);

    // Get iterator to all the rows in current sheet
    Iterator<Row> rowIterator = mySheet.iterator();

    // Traversing over each row of XLSX file
    while (rowIterator.hasNext()) {
        Row row = rowIterator.next();

        // For each row, iterate through each columns
        Iterator<Cell> cellIterator = row.cellIterator();
        while (cellIterator.hasNext()) {

            Cell cell = cellIterator.next();

            switch (cell.getCellType()) {
            case Cell.CELL_TYPE_STRING:
                System.out.print(cell.getStringCellValue() + "\t");
                break;
            case Cell.CELL_TYPE_NUMERIC:
                System.out.print(cell.getNumericCellValue() + "\t");
                break;
            case Cell.CELL_TYPE_BOOLEAN:
                System.out.print(cell.getBooleanCellValue() + "\t");
                break;
            default :

            }
        }
        System.out.println("");
    }
}

Answer 5

这工作正常：尝试一下

File filename = new File("E:/Test.xlsx");
FileInputStream isr= new FileInputStream(filename);

Workbook book1 = new XSSFWorkbook(isr);
Sheet sheet = book1.getSheetAt(0);  
Iterator<Row> rowItr = sheet.rowIterator();

Answer 6

public class ExcelReader{
   public String path;
   public static FileInputStream fis;

   public ExcelReader(){
      System.out.println("hello");
   }

   public ExcelReader(String path){
      this.path=path;
      fis=new FileInputStream(path);
      XSSFWorkbook workbook=new XSSFWorkbook(fis);
      XSSFSheet sheet=workbook.getSheet("Sheet1");//name of the sheet
      System.out.println(sheet.getSheetName());
      System.out.println(sheet.getLastRowNum());
      System.out.println(sheet.getRow(2).getCell(3));
  }
  public static void main(String[] args) throws IOException {
      ExcelReader excel=new ExcelReader("path of xlsx");
  }
}

Answer 7

我有同样的错误，我刚刚用相同的版本更新了 pom 依赖项。它起作用了。

        <!-- https://mvnrepository.com/artifact/org.apache.poi/poi -->
        <dependency>
            <groupId>org.apache.poi</groupId>
            <artifactId>poi</artifactId>
            <version>4.1.0</version>
        </dependency>
        <!-- https://mvnrepository.com/artifact/org.apache.poi/poi-ooxml -->
        <dependency>
            <groupId>org.apache.poi</groupId>
            <artifactId>poi-ooxml</artifactId>
            <version>4.1.0</version>
        </dependency>

Answer 8

// Load sheet- Here we are loading first sheet only
XSSFSheet xlSheet = wb.getSheetAt(0);

这里的代码仅识别第一张工作表 - 在我的 Excel 中存在多个工作表，因此面临将 sheet2 更改为 sheet1(getSheetAt(0)) 的问题...