使用 id 而不是对象创建 JPA 多对多关系
我有一个大型数据集,我正在批量导入该数据集,其中的行看起来像
(news_id, category_id_1, category_id_2, ..., category_id_9)
每个 category_id_x
都是来自一组固定类别的整数。
我想将这些多个类别映射到 m2m 关系中,以便更快地搜索。
我有一个 News
表和一个 Category
表。
Category
表将类别 ID 映射到类别名称。
我已经在 JPA 中为各种 News
字段设置了所有映射,并且我想重用此代码。
我的问题是如何在 JPA 中导入这些 m2m 关系。
我正在考虑以下内容,但收到错误消息,指出您无法手动创建类别对象。
// News object
@Entity
@Table(name = "news", schema = "public", uniqueConstraints = {})
public class News implements java.io.Serializable {
// Fields
@Column(name = "asx_code")
private String asxCode;
@Id
@Column(name = "annnum", unique = true, nullable = false)
private String annnum;
@Column(name = "company_name")
private String companyName;
...
...
@ManyToMany()
@JoinTable(name="announcement_types",
joinColumns= @JoinColumn(name="annnum"),
inverseJoinColumns=@JoinColumn(name="report_type"))
private Collection<ReportType> reportType;
function m(String) {
// extract and return data from datasource
}
// Create a news object from 9 different report types
News o = new News();
java.util.Collection<ReportType> types = new HashSet();
types.add(new ReportType(toInt(m("RepType0"))));
types.add(new ReportType(toInt(m("RepType1"))));
types.add(new ReportType(toInt(m("RepType2"))));
types.add(new ReportType(toInt(m("RepType3"))));
types.add(new ReportType(toInt(m("RepType4"))));
types.add(new ReportType(toInt(m("RepType5"))));
types.add(new ReportType(toInt(m("RepType6"))));
types.add(new ReportType(toInt(m("RepType7"))));
types.add(new ReportType(toInt(m("RepType8"))));
types.add(new ReportType(toInt(m("RepType9"))));
o.setReportType(types);
// Query
try {
EntityTransaction entr = em.getTransaction();
entr.begin();
em.persist(row); # row is our News object
entr.commit();
} catch (Exception e) {
e.printStackTrace();
return false;
}
return true;
// ERROR
SEVERE: Could not synchronize database state with session
org.hibernate.TransientObjectException: object references an unsaved transient instance - save the transient instance before flushing: edu.unsw.eventstudy.shared.dto.ReportType
编辑:
似乎我正在处理独立实体的概念。在 Hibernate 中,可以使用未保存值映射或 isSaved 属性解决此问题。现在在JPA中寻找解决方案。
I have a large dataset which I am importing in bulk with rows looking like
(news_id, category_id_1, category_id_2, ..., category_id_9)
Each category_id_x
is an integer from a fixed set of categories.
I want to map these multiple categories into a m2m relation for quicker searching.
I have a News
table and a Category
table.
The Category
table maps category ids to category names.
I already have all the mappings setup in JPA for the various News
fields, and I want to reuse this code.
My question is how can I import these m2m relations in JPA.
I was thinking along the lines of the following but I get errors saying that you can't create Category objects manually.
// News object
@Entity
@Table(name = "news", schema = "public", uniqueConstraints = {})
public class News implements java.io.Serializable {
// Fields
@Column(name = "asx_code")
private String asxCode;
@Id
@Column(name = "annnum", unique = true, nullable = false)
private String annnum;
@Column(name = "company_name")
private String companyName;
...
...
@ManyToMany()
@JoinTable(name="announcement_types",
joinColumns= @JoinColumn(name="annnum"),
inverseJoinColumns=@JoinColumn(name="report_type"))
private Collection<ReportType> reportType;
function m(String) {
// extract and return data from datasource
}
// Create a news object from 9 different report types
News o = new News();
java.util.Collection<ReportType> types = new HashSet();
types.add(new ReportType(toInt(m("RepType0"))));
types.add(new ReportType(toInt(m("RepType1"))));
types.add(new ReportType(toInt(m("RepType2"))));
types.add(new ReportType(toInt(m("RepType3"))));
types.add(new ReportType(toInt(m("RepType4"))));
types.add(new ReportType(toInt(m("RepType5"))));
types.add(new ReportType(toInt(m("RepType6"))));
types.add(new ReportType(toInt(m("RepType7"))));
types.add(new ReportType(toInt(m("RepType8"))));
types.add(new ReportType(toInt(m("RepType9"))));
o.setReportType(types);
// Query
try {
EntityTransaction entr = em.getTransaction();
entr.begin();
em.persist(row); # row is our News object
entr.commit();
} catch (Exception e) {
e.printStackTrace();
return false;
}
return true;
// ERROR
SEVERE: Could not synchronize database state with session
org.hibernate.TransientObjectException: object references an unsaved transient instance - save the transient instance before flushing: edu.unsw.eventstudy.shared.dto.ReportType
EDIT:
Seems I am dealing with the concept of detached entities. This is solved in Hibernate using the unsaved-value mapping or isSaved property. Now looking for a solution in JPA.
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我只看到 1 个方向的关联。也许您忘记执行另一项操作,例如:
reportType0.add(新闻);
reportType1.add(新闻);
...
reportTypeN.add(新闻);
此外,您正在“创建”ReportType 的实例,而不是从数据库中收集它们。它们是否已存在于数据库中?
I only see the association in 1 direction. Maybe you forgot to do the other one, like:
reportType0.add(news);
reportType1.add(news);
...
reportTypeN.add(news);
Also, you are "creating" instances of the ReportType instead of gathering them from the database. Do they already exist in the database?