在密码强度检查器中使用一系列不可用的单词

发布于 2024-11-07 05:37:41 字数 454 浏览 0 评论 0原文

我是 jQuery 新手，目前正在修改 Firas Kassem 的密码强度计，并希望检查一系列不允许的单词。我遇到了这个问题作为起点。我目前所拥有的是：

var badArr = ['password','system','user','demo','test','default'] //Array of unusable words
//check if bad words are in password
$.each(badArr, function(index,value)
{
    if(password.match(value))
        return badPass
})

问题是它不返回 badPass。对我做错了什么有任何见解吗？

原文

I'm new to jQuery and am currently working on modifying Firas Kassem's password strength meter and wanted to check against an array of disallowed words. I came across this question for a starting point. What I have currently is:

var badArr = ['password','system','user','demo','test','default'] //Array of unusable words
//check if bad words are in password
$.each(badArr, function(index,value)
{
    if(password.match(value))
        return badPass
})

The problem is that it doesn't return the badPass. Any insight on what I'm doing wrong?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

蓝眼睛不忧郁 2024-11-14 05:37:41

实际上，我已经建立了自己的力量计，因为我不需要力量计；只是一个需求检查器。

通过使用简单的password.match和正则表达式，我能够检查这些特定的单词。给我的要求没有指定大小写字母，所以我做了一个简单的匹配。

 password.match(/((SYSTEM)|(Password)|(Default)|(USER)|(Demo)|(TEST))/)

我还可以使用不同的算法检查以下内容。

 //password != user name, first name, or last name
 //password != 6 chars, 6 nums, or 6 symbols
 //password != social security numbers
 //password != a date
 //password = 3 of 4 requirements (upper, lower, num, char)

一个有用的网站是 www.regular-expressions.info

I've actually built my own since I don't have the need for a strength meter; just a requirements checker.

By using a simple password.match using a regular expression, I was able to check for these certain words. The requirements that were given to me didn't specify upper or lower case letters, so I did a simple match.

 password.match(/((SYSTEM)|(Password)|(Default)|(USER)|(Demo)|(TEST))/)

I was also able to check for the below using different algorithms.

 //password != user name, first name, or last name
 //password != 6 chars, 6 nums, or 6 symbols
 //password != social security numbers
 //password != a date
 //password = 3 of 4 requirements (upper, lower, num, char)

A helpful site was www.regular-expressions.info

回复收藏 0 原文

~没有更多了~