想要 Shell 魔法：在管道中格式化 hexdump 的输出

发布于 2024-11-07 05:29:10 字数 1166 浏览 0 评论 0原文

我正在调试通过 TCP 传输数据的程序的输出。出于调试目的，我用 netcat 和 hexdump 替换了接收程序：

netcat -l -p 1234 | hexdump -C

它将所有数据输出为一个漂亮的十六进制转储，几乎就像我想要的那样。现在，数据以固定块的形式传输，其长度不是 16 的倍数，导致输出中的行发生移位，从而使发现差异变得有点困难：

00000000  50 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |P...............|
00000010  00 50 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |.P..............|
00000020  00 00 50 00 00 00 00 00  00 00 00 00 00 00 00 00  |..P.............|

如何重新格式化输出，以便在 17 个字节后开始新行？它应该看起来像这样：

50 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |P...............|
00                                                |.               |
50 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |P...............|
00                                                |.               |
50 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |P...............|
00                                                |.               |

使用 hexdumps -n 参数不起作用，因为它会在达到字节数后退出。（除非有办法保持 netcat 程序运行并将下一个字节无缝管道传输到新的 hexdump 实例）。

另外，如果我可以在输出上使用 watch -d 来突出显示行之间的更改，那就太好了。

原文

I'm debugging the output of a program that transmits data via TCP.
For debugging purposes i've replaced the receiving program with netcat and hexdump:

netcat -l -p 1234 | hexdump -C

That outputs all data as a nice hexdump, almost like I want. Now the data is transmitted in fixed blocks which lengths are not multiples of 16, leading to shifted lines in the output that make spotting differences a bit difficult:

00000000  50 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |P...............|
00000010  00 50 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |.P..............|
00000020  00 00 50 00 00 00 00 00  00 00 00 00 00 00 00 00  |..P.............|

How do I reformat the output so that after 17 bytes a new line is started?
It should look something like this:

50 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |P...............|
00                                                |.               |
50 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |P...............|
00                                                |.               |
50 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |P...............|
00                                                |.               |

Using hexdumps -n parameter does not work since it will exit after reaching the number of bytes. (Unless there is a way to keep the netcat programm running and seamlessly piping the next bytes to a new instance of hexdump).

Also it would be great if I could use watch -d on the output to get a highlight of changes between lines.

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菊凝晚露 2024-11-14 05:29:10

对于没有字符部分的十六进制转储。

hexdump -e '16/1 "%0.2x " "\n" 1/1 "%0.2x " "\n"'

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一世旳自豪 2024-11-14 05:29:10

我使用这个：

use strict;
use warnings;
use bytes;

my $N = $ARGV[0];

$/ = \$N;

while (<STDIN>) {
    my @bytes = unpack("C*", $_);
    my $clean = $_;
    $clean =~ s/[[:^print:]]/./g;
    print join(' ', map {sprintf("%2x", $_)} @bytes),
    "  |", $clean, "|\n";
}

将其作为 perl scriptname.pl N 运行，其中 N 是您想要的每个块中的字节数。

I use this:

use strict;
use warnings;
use bytes;

my $N = $ARGV[0];

$/ = \$N;

while (<STDIN>) {
    my @bytes = unpack("C*", $_);
    my $clean = $_;
    $clean =~ s/[[:^print:]]/./g;
    print join(' ', map {sprintf("%2x", $_)} @bytes),
    "  |", $clean, "|\n";
}

Run it as perl scriptname.pl N where N is the number of bytes in each chunk you want.

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