如何在 Selenium 2 API 中处理鼠标悬停

Question

String strPrimaryNav = "MEN";
String strSecondaryNav = "Shoes";
String strTertiaryNav = "Golf";

driver.findElement(By.linkText(strPrimaryNav)).click();

WebElement weSecNav = driver.findElement(By.className("secondaryButton").linkText(strSecondaryNav));

Mouse mouse = ((HasInputDevices) driver).getMouse();
mouse.mouseDown(((Locatable)weSecNav).getCoordinates());
//just trying with for loop as the tertiary popup disappears quickly and hence getting ElementNotVisible Exception
for (int i = 0 ; i< 2; i++){
    mouse.mouseDown(((Locatable)weSecNav).getCoordinates());
    //mouse.mouseMove(((Locatable)weSecNav).getCoordinates(), 0, 0 );
    //WebElement weTerNav = driver.findElement(By.className("tertiaryButton").linkText(strTertiaryNav));
    WebElement weTerNav = driver.findElement(By.linkText(strTertiaryNav));
    boolean isSecDisplayed = ((RenderedWebElement)weTerNav).isDisplayed();
    System.out.println("isDisplayed: " + isSecDisplayed);
    System.out.println(" " + ((RenderedWebElement)weSecNav).getAttribute("href"));
    System.out.println(" " + ((RenderedWebElement)weSecNav).getValueOfCssProperty("action"));
    weTerNav.click();
}

我正在尝试使用 selenium 2 编写下面的代码，但是，第三级弹出窗口不会停留很长时间来单击它，因此在第三级单击时会出现 ElementNotVisible 异常。

Answer 1

您至少可以在发送点击之前检查该元素是否可见：

Selenium s = new WebDriverBackedSelenium( driver, URL );
s.waitForCondition( "!( document.getElementById('.....') === null )", "20000" );
s.click( .... );

这可以避免出现异常。我不确定是否有办法让弹出窗口停留的时间比应有的时间长。