Spring mvc 分页

Question

你好，我在我的项目中使用 jqgrid，我需要实现分页，所以我在 php 中找到了一个代码并将其复制到 java ：

@RequestMapping(value = "getgriddata", method = RequestMethod.GET)
    public @ResponseBody
    String getGrid(@RequestParam("page") String page, @RequestParam("rows") int rownumber, @RequestParam("sidx") String sortBy, @RequestParam("sord") String sortOrder,@RequestParam(value = "_search") String search, @RequestParam(value="filters", required = false) String filters) {

        int totalCount = dao.getTotalRecordCount();

        CustomJsonResponse response = new CustomJsonResponse();

        int totalPages = 0;

        if (totalCount > 0) {
            totalPages = (int) Math.ceil(totalCount/rownumber);
        }

        if (Integer.valueOf(page) > totalPages) {
            page = String.valueOf(totalPages);
        }

        Gson jsonConverter = new Gson();

        int start = (rownumber * Integer.valueOf(page)) - rownumber;
        Filters searchFilter = null;

        if(Boolean.valueOf(search) == true){
            searchFilter = jsonConverter.fromJson(filters, Filters.class);
        }

        // Retrieve records from database
        List<Record> recorBatch = dao.getRecords(start, rownumber, sortBy, sortOrder, search, searchFilter);

        // Assign the result from the service to this response
        response.setRows(recorBatch);
        response.setTotal(String.valueOf(totalPages));
        response.setRecords(String.valueOf(stagingLoadBatch.size()));
        response.setPage(page);

        return jsonConverter.toJson(response);
    }

当我处理整个数据集时，这可以正常工作，但是当我缩小范围时搜索，即选择某个时间间隔内的记录，然后分页失败。我意识到这是不好的做法，我从这段代码中复制了它以进行分页：

http://pastebin.com/ybKSXzyq

有人可以为此提出更好的解决方案吗？

Answer 1

我建议您查看显示标签库进行分页。

Answer 2

我正在完整实现它，我做了 JQGridPage.java 类来包含 jqgrid 的数据

public class JQGridPage<T> {

    private Integer page;
    private Integer total;
    private Long records;
    private List<T> rows;
....
}

，并在控制器方法中填充它并将其作为方法的返回发送

@RequestMapping(value = "", method = RequestMethod.GET, params = "page")
@ResponseBody
public JQGridPage<T> listPages(
        @RequestParam(value = "page", defaultValue = "1") int page,
        @RequestParam(value = "rows", defaultValue = "10") int rows,
        @RequestParam(value = "sidx", defaultValue = "id") String sortField,
        @RequestParam(value = "sord", defaultValue = "ASC") String sortDirection,
        @RequestParam(value = "searchField", defaultValue = "id") String searchField,
        @RequestParam(value = "searchOper", defaultValue = "eq") String searchOper,
        @RequestParam(value = "searchString", defaultValue = "") String searchString) {
.....
    JQGridPage<T> jqGrid = new JQGridPage<T>();
    jqGrid.setPage(page);
    jqGrid.setTotal(pageOfCustomer.getTotalPages());
    jqGrid.setRecords(pageOfCustomer.getTotalElements());
    jqGrid.setRows(pageOfCustomer.getContent());
    return jqGrid;
}

Answer 3

这是我在 Spring MVC 中的分页结果