无法回显该值

发布于 2024-11-07 01:26:06 字数 344 浏览 3 评论 0原文

我只是尝试从 mysql 数据库检索一个值，并尝试使用 php 函数打印该值。但这不起作用:(请帮忙。

<?php
include("connection.php");
$con=mysql_query("SELECT times FROM counts WHERE item='applemenu';");
$info = mysql_fetch_array($con);
$count==$info['times'];
?>

在一些 html 标签之后

<?php echo $count;?>

有什么问题吗？

原文

I just tried to retrieve a value from my mysql databade and tried to print that using php function. But this is not working :( Please help.

<?php
include("connection.php");
$con=mysql_query("SELECT times FROM counts WHERE item='applemenu';");
$info = mysql_fetch_array($con);
$count==$info['times'];
?>

after some html tags

<?php echo $count;?>

Is there anything wrong ?

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小耗子 2024-11-14 01:26:06

$count==$info['times'];

将此更改为

$count=$info['times'];

$count==$info['times'];

change this to

$count=$info['times'];

回复收藏 0 原文

救赎№ 2024-11-14 01:26:06

<?php
 include("connection.php");
 $input = 'applemenu';
 $stmt = mysqli_prepare($con,"SELECT times FROM counts WHERE item=?");
 mysqli_stmt_bind_param($stmt,"s",$input);
 mysqli_stmt_execute($stmt);
 mysqli_stmt_bind_result($stmt, $count);
 mysqli_stmt_fetch($stmt);
 mysqli_stmt_close($stmt);
 mysqli_close($con);

 echo $count;
?>

<?php
 include("connection.php");
 $input = 'applemenu';
 $stmt = mysqli_prepare($con,"SELECT times FROM counts WHERE item=?");
 mysqli_stmt_bind_param($stmt,"s",$input);
 mysqli_stmt_execute($stmt);
 mysqli_stmt_bind_result($stmt, $count);
 mysqli_stmt_fetch($stmt);
 mysqli_stmt_close($stmt);
 mysqli_close($con);

 echo $count;
?>

回复收藏 0 原文

棒棒糖 2024-11-14 01:26:06

<?php
include("connection.php");
$con=mysql_query("SELECT times FROM counts WHERE item='applemenu';");
$info = mysql_fetch_array($con);
$count= $info['times'];// This was the wrong with == operator
?>

在一些 html 标签之后

<?php echo '$count';?>

<?php
include("connection.php");
$con=mysql_query("SELECT times FROM counts WHERE item='applemenu';");
$info = mysql_fetch_array($con);
$count= $info['times'];// This was the wrong with == operator
?>

after some html tags