如何跟踪 C 中结构成员值的变化？

Question

struct STATE{
  uint8 bit;
  uint8 cop;
}
STATE *state_array[1024];

state_aray[0]->bit = 8;     
state_aray[0].cop =  8;
state_aray[1]->bit = 0;     
state_aray[1].cop = state_aray[1]->bit & 8 != state_aray[0]->bit & 8
state_aray[2]->bit = 12;   
state_aray[2].cop = state_aray[1]->bit & 8 != state_aray[0]->bit & 8 && state_aray[2]->bit & 8 != state_aray[1]->bit & 8
state_aray[3]->bit = 0;     
state_aray[3].cop = state_aray[1]->bit & 8 != state_aray[0]->bit & 8 && state_aray[2]->bit & 8 != state_aray[1]->bit & 8 && state_aray[3]->bit & 8 != state_aray[2]->bit & 8
state_aray[4]->bit = 8;     
state_aray[4].cop = ...

state_aray[5].cop = ... ...
...
state_aray[100].cop = ... ...... ......... ....... ......... ....... ...... ....... ............... ........ ...... ............ .... ......... ...... ..

有没有办法只使用 state_aray[i-1]->cop 和 state_aray[i-1]->bit 和 state_aray[i]->bit 来获取 state_aray[i]->cop？

tks

Answer 1

行不通。与 OOP 的“this”或“self”概念相反，C 中不存在“我是该结构的成员”机制。
这就是为什么在 C 中，您只需隐藏结构实现并提供函数来更改您偷偷设置其他值的值。

STATE *create_state(void)
{
    STATE *retval;

    if( (retval = malloc(sizeof(STATE))) == NULL )
        return NULL;
    retval->cop = -1;
    retval->bit = 0;
    return retval;
}

void set_state(STATE *st, int val)
{
    st->bit = val;
    st->cop++;
}

int has_state_changed(STATE *st)
{
    return st->cop;
}