从 C# 运行带有参数的命令行？

发布于 2024-11-06 15:00:49 字数 345 浏览 0 评论 0原文

可以使用如下方式在 C# 中运行命令行：

process = new Process();
process.StartInfo.FileName = command;
process.Start();

问题是命令字符串是否包含参数，例如：

C:\My Dir\MyFile.exe MyParam1 MyParam2

这将不起作用，我不知道如何从该字符串中提取参数并将其设置在 < code>process.Arguments 属性？路径和文件名可以是其他名称，文件不必以 exe 结尾。

我该如何解决这个问题？

原文

It's possible to run commandline in c# by using something like this :

process = new Process();
process.StartInfo.FileName = command;
process.Start();

The problem is if the command string contains parameters, for example:

C:\My Dir\MyFile.exe MyParam1 MyParam2

This will not work and I don't see how to extract the parameters from this string and set it on the process.Arguments property? The path and filename could be something else, the file does not have to end with exe.

How can I solve this?

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葬﹪忆之殇 2024-11-13 15:00:49

如果我理解正确，我会使用：

string command = @"C:\My Dir\MyFile.exe";
string args = "MyParam1 MyParam2";

Process process = new Process(); 
process.StartInfo.FileName = command; 
process.StartInfo.Arguments = args;
process.Start();

如果您有一个需要解析的完整字符串，我会使用其他人在这里提出的其他方法。如果您想向流程添加参数，请使用上面的内容。

If I understand correctly I would use:

string command = @"C:\My Dir\MyFile.exe";
string args = "MyParam1 MyParam2";

Process process = new Process(); 
process.StartInfo.FileName = command; 
process.StartInfo.Arguments = args;
process.Start();

If you have a complete string that you need to parse I would use the other methods put forward by the others here. If you want to add parameters to the process, use the above.

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心作怪 2024-11-13 15:00:49

这可能是最糟糕的解决方案，但也可能是一种更安全的解决方案：

string cmd = "C:\\My Dir\\MyFile.exe MyParam1 MyParam2";
System.IO.FileInfo fi = null;
StringBuilder file = new StringBuilder();
// look up until you find an existing file
foreach ( char c in cmd )
{
    file.Append( c );
    fi = new System.IO.FileInfo( file.ToString() );
    if ( fi.Exists ) break;
}

cmd = cmd.Remove( 0, file.Length );
System.Diagnostics.ProcessStartInfo psi = new System.Diagnostics.ProcessStartInfo( fi.Name, cmd );
System.Diagnostics.Process.Start( psi );

This could be the worst solution, but it could a safer one:

string cmd = "C:\\My Dir\\MyFile.exe MyParam1 MyParam2";
System.IO.FileInfo fi = null;
StringBuilder file = new StringBuilder();
// look up until you find an existing file
foreach ( char c in cmd )
{
    file.Append( c );
    fi = new System.IO.FileInfo( file.ToString() );
    if ( fi.Exists ) break;
}

cmd = cmd.Remove( 0, file.Length );
System.Diagnostics.ProcessStartInfo psi = new System.Diagnostics.ProcessStartInfo( fi.Name, cmd );
System.Diagnostics.Process.Start( psi );

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