从模板派生

发布于 2024-11-06 14:35:10 字数 691 浏览 4 评论 0原文

我陷入了以下困境，需要一些帮助：

typedef unsigned short USHORT;

template <typename DataType>
class Primative
{
protected:
    DataType m_dtValue;
public:
    Primative() : m_dtValue(0) {}

    DataType operator=(const DataType c_dtValue) { return m_dtValue = c_dtValue; }
    DataType Set(const DataType c_dtValue){ return m_dtValue = c_dtValue; }
};

typedef Primative<USHORT> PrimativeUS;

class Evolved : public PrimativeUS
{
public:
    Evolved() {}
};

int main()
{
    PrimativeUS prim;
    prim = 4;

    Evolved evo;
    evo.Set(5);  // good
    evo = USHORT(5); // error, no operator found which takes a right-hand operator...
}

看起来派生类没有获得重载运算符

原文

I'm stuck on the following and could use some help:

typedef unsigned short USHORT;

template <typename DataType>
class Primative
{
protected:
    DataType m_dtValue;
public:
    Primative() : m_dtValue(0) {}

    DataType operator=(const DataType c_dtValue) { return m_dtValue = c_dtValue; }
    DataType Set(const DataType c_dtValue){ return m_dtValue = c_dtValue; }
};

typedef Primative<USHORT> PrimativeUS;

class Evolved : public PrimativeUS
{
public:
    Evolved() {}
};

int main()
{
    PrimativeUS prim;
    prim = 4;

    Evolved evo;
    evo.Set(5);  // good
    evo = USHORT(5); // error, no operator found which takes a right-hand operator...
}

It looks like the derived class is not getting the overloaded operator

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迷爱 2024-11-13 14:35:10

试试这个：

class Evolved : public PrimativeUS
{
public:
  using PrimativeUS::operator=;
  Evolved() {}
};

为您提供的隐式 Evolved::operator=(const Evovled&) 隐藏了基类中存在的 operator= 的所有实例。（任何方法都是如此 - 派生类的方法隐藏基类的类似命名的方法，即使签名不匹配。）

Try this:

class Evolved : public PrimativeUS
{
public:
  using PrimativeUS::operator=;
  Evolved() {}
};

The implicit Evolved::operator=(const Evovled&) that is provided for you hides all instances of operator= present in the base class. (This is true of any method - methods of derived classes hide similarly-named methods of base class, even if the signatures don't match.)

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ま昔日黯然 2024-11-13 14:35:10

稍微改变你的函数声明：

DataType operator=(const DataType& c_dtValue) { return m_dtValue = c_dtValue; }
DataType Set(const DataType& c_dtValue){ return m_dtValue = c_dtValue; }

注意 a &运算符重载需要（参考）符号。

Change your function declaration slightly:

DataType operator=(const DataType& c_dtValue) { return m_dtValue = c_dtValue; }
DataType Set(const DataType& c_dtValue){ return m_dtValue = c_dtValue; }

Note that a & (reference) sign is needed for operator overloading.

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