在 C# 函数中使用 JSONResult

发布于 2024-11-06 08:30:49 字数 407 浏览 0 评论 0原文

我有一个以下面的方式返回 JsonResult 的函数。

var attachments = (from a in ar.Attachments 
  select new { id = a.Id, filename = a.FileName }).ToArray(); 
var result = new
            {
                comments = "Some string",
                attachments = attachments
            };

        return this.Json(result);

我需要在另一个类中使用这个结果，我需要访问“评论”和“附件”。这里附件是一个字符串数组，注释是一个字符串。请让我知道我该怎么做。

原文

I have a function which returns a JsonResult in the below way.

var attachments = (from a in ar.Attachments 
  select new { id = a.Id, filename = a.FileName }).ToArray(); 
var result = new
            {
                comments = "Some string",
                attachments = attachments
            };

        return this.Json(result);

I need to use this result in another class where I need to access the "comments" and "attachments". Here attachments is a string array and comments is a string. Please let me know how I can do this.

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爱冒险 2024-11-13 08:30:49

您可以为结果创建一个 ViewModel，然后重用该类。 ViewModel 的全部内容只是 POCO 或 DTO。这个想法是，它为您提供了一种不同的方式来“查看”数据，实际上没什么特别的。

所以你最终得到了 3 个部分。

获取数据方法：

public CommentsViewModel GetViewModel()
{
    var attachments = 
        (from a in ar.Attachments 
        select new { id = a.Id, filename = a.FileName }).ToArray(); 
    var result = new CommentsViewModel
            {
                comments = "Some string",
                attachments = attachments
            };

    return result;
}

您的控制器方法：

public JsonResult Get()
{
    return this.Json(GetViewModel());
}

您的其他方法将直接调用 GetViewModel()。这将为您将其分开一点。

You could create a ViewModel for the result and then just reuse that class. All a ViewModel is, is just a POCO or DTO. The idea is that it gives you a different way to "look" at your data, nothing special really.

So you end up with 3 parts.

The get data method:

public CommentsViewModel GetViewModel()
{
    var attachments = 
        (from a in ar.Attachments 
        select new { id = a.Id, filename = a.FileName }).ToArray(); 
    var result = new CommentsViewModel
            {
                comments = "Some string",
                attachments = attachments
            };

    return result;
}

Your controller method:

public JsonResult Get()
{
    return this.Json(GetViewModel());
}

And your other method would just call GetViewModel() directly. This would separate this out a bit for you.

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一影成城 2024-11-13 08:30:49

好的，所以这是一个我认为应该使用 dynamic 类型满足您需求的答案...

这是您在控制器上调用的方法...我已经放入了“硬编码”示例数据根据您对此示例的要求...我从注释中删除了“s”，只是因为：

public JsonResult GetJsonData()
{
    var result = new
        {
            comment = "Some string",
            attachments = new string[]{"/folder/file-1.jpg", "/folder/file-2.jpg"}
        };

        return this.Json(result);
}

直接调用控制器操作并读取 JsonResult 的代码：

dynamic result = GetJsonData().Data;

//var comment will result in a string which equals "Some string" in this example
var comment = result.comment;

//var attachments will result in a string[] which is equal to new string[]{"/folder/file-1.jpg", "/folder/file-2.jpg"}
var attachments = result.attachments;

Ok, so here is an answer that I believe should fit your needs using the dynamic type...

This is the method you call on the controller...I have put in 'hard coded' sample data as per your requirements for this example...I've removed the 's' from comments just because:

public JsonResult GetJsonData()
{
    var result = new
        {
            comment = "Some string",
            attachments = new string[]{"/folder/file-1.jpg", "/folder/file-2.jpg"}
        };

        return this.Json(result);
}

The code that calls the controller action directly and reads the JsonResult:

dynamic result = GetJsonData().Data;

//var comment will result in a string which equals "Some string" in this example
var comment = result.comment;

//var attachments will result in a string[] which is equal to new string[]{"/folder/file-1.jpg", "/folder/file-2.jpg"}
var attachments = result.attachments;

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