Rails Metasearch 未定义方法 'company_id'
我是 Rails 新手，需要您的帮助来解决一个简单的问题。
当我运行此代码时：
@search = User.search(params[:search])
@foundusers = @search.all.paginate :page => params[:page], :per_page => 20
@user = @search.where("users.id = ?", params[:id])
if @user.nil?
@user = @foundusers.first
end
unless @user.company_id.nil?
@company = Company.find(@user.company_id)
end
我收到以下错误语句： undefined method `company_id' for #
我不明白，因为数据库上的查询是正确的（SELECT users.* FROM users LEFT OUTER JOIN companies ON 公司.id = 用户.company_id WHERE (((用户.< code>firstname LIKE '%s%' OR users.lastname LIKE '%s%') OR 公司.name LIKE '%s%')) AND (users.id = '11'))
并且该用户的 company_id 不为空。
当我输入 put @user.name 时，它没有给我用户名，而是给我“用户”
非常感谢您的帮助。
I'm new to rails and need your help for what should be a simple problem.
when I run this code:
@search = User.search(params[:search])
@foundusers = @search.all.paginate :page => params[:page], :per_page => 20
@user = @search.where("users.id = ?", params[:id])
if @user.nil?
@user = @foundusers.first
end
unless @user.company_id.nil?
@company = Company.find(@user.company_id)
end
I get following error statement:
undefined method `company_id' for #
I dont understand because the query on the database is correct (SELECT users.* FROM users LEFT OUTER JOIN companies ON companies.id = users.company_id WHERE (((users.firstname LIKE '%s%' OR users.lastname LIKE '%s%') OR companies.name LIKE '%s%')) AND (users.id = '11'))
and the company_id for this user is not empty.
When I type puts @user.name, instead of giving me the user name, it gives me 'User'
Many thanks for your help.
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@user.name 打印 User 因为 .where("users.id = ?", params[:id]) 仍然返回一个数组
试试这个
@user.name prints User because .where("users.id = ?", params[:id]) still return an array
Try this