确保 PHP 关闭函数被调用
我试图在 PHP 中捕获尽可能多的错误，并以非默认方式正确处理它们。我的问题在这个例子中得到了最好的说明：
<?php
function errorHandler($errno, $errstr, $errfile, $errline){
echo "Error handler here <br>\n";
//throw new Exception($errstr);
}
function shutdownFunction() {
echo "Hi I'm in here <br>\n";
}
set_error_handler("errorHandler");
register_shutdown_function("shutdownFunction");
try {
$undefined->ok(); // causes some error
} catch(Exception $e) {
echo "Caught the exception <br>\n";
}
作为 PHP 程序运行此代码的结果将表明 errorHandler() 已运行，会打印 PHP 错误（如果“display_errors”设置为“On ")，然后运行 shutdownFunction()。
如果我取消注释该异常抛出，就会出现我遇到的问题；我想尽可能频繁地抛出 PHP 错误异常。如果我取消注释 throw 语句，则会调用错误处理程序，该处理程序会引发异常，从而导致进一步的错误，从而导致 shutdownFunction() 不被调用。
据我了解，我不能将此错误变成可捕获的异常；但是，我至少想确保调用关闭函数时不会限制我捕获至少一些 php 错误作为异常的能力（这意味着我不想删除该 throw< errorHandler() 中的 /code> 语句）。
我可以在 errorHandler 中进行一些检查来检查抛出它是否会导致 shutdownFunction() 被绕过吗？
I'm trying to catch as many errors as possible in PHP and properly handle them in a non-default way. My question is best illustrated in this example:
<?php
function errorHandler($errno, $errstr, $errfile, $errline){
echo "Error handler here <br>\n";
//throw new Exception($errstr);
}
function shutdownFunction() {
echo "Hi I'm in here <br>\n";
}
set_error_handler("errorHandler");
register_shutdown_function("shutdownFunction");
try {
$undefined->ok(); // causes some error
} catch(Exception $e) {
echo "Caught the exception <br>\n";
}
The result of running this code as a PHP program will indicate that errorHandler() is run, a PHP error is printed (if "display_errors" is set to "On"), and then shutdownFunction() is run.
The problem I'm having arises if I uncomment out that exception throw; I want to throw exceptions on PHP errors as often as possible. If I uncomment the throw statement out, then the error handler is called, which throws an exception thus causing a further error which results in shutdownFunction() not to be called.
It is my understanding that I can't make this error into a catchable exception; however, I would at least like to ensure that the shutdown function is called without restricting my ability to catch at least some php errors as exceptions (meaning I don't want to remove that throw statement in errorHandler()).
Is there some check in the errorHandler that I can do to check whether or not throwing it will cause shutdownFunction() to be bypassed?
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从错误处理程序中抛出异常，然后使用 set_exception_handler 处理未捕获的异常。
Throw an exception from the error handler, then use set_exception_handler to handle uncaught exceptions.
所以我解决这个问题的方法是检查 $errstr 参数是否以“未定义变量”开头 - 如果是，那么我不会抛出异常。我想如果还有任何其他错误有类似的问题，我也会对它们做同样的事情。我找不到 php 错误的完整列表及其影响，所以它必须是临时的
So the way I'm solving this is to check if the $errstr parameter starts with "Undefined variable" - and if it does, then I'm not throwing the exception. I suppose if there are any other errors that have a similar issue, i'll do the same thing with those. I can't find a comprehensive list of php errors and what their affects are though, so it'll have to be ad hoc