以下 GCD / 块场景的推荐模式是什么？

发布于 2024-11-06 04:50:27 字数 403 浏览 0 评论 0原文

我有一个关于 Grand Central Dispatch、块和内存管理的问题。考虑以下代码：

Worker *myWorker = [[Worker alloc] init];
[work doAsyncStuffWithBlock:^(NSMutableDictionary *info)
{
    NSLog(@"processing info results");
}];
[myWorker release];

在这里，我希望 doAsyncStuffWithBlock 异步发生，然后在有一些结果时执行该块。同时这个主要代码还会继续。在这里释放 myWorker 安全吗？我在内部实现的dispatch_queue是否会保留它的引用以最终执行该块？或者，我应该在块内释放它吗？这看起来很奇怪。感谢您的任何建议。

原文

I have a question about Grand Central Dispatch, blocks and memory management. Consider this code:

Worker *myWorker = [[Worker alloc] init];
[work doAsyncStuffWithBlock:^(NSMutableDictionary *info)
{
    NSLog(@"processing info results");
}];
[myWorker release];

Here, I want the doAsyncStuffWithBlock to happen asynchronously and then perform the block when it has some results. Meanwhile this main code will continue on. Is it safe here to release myWorker? Will the dispatch_queue I implement internally keep a reference of it around to eventually execute that block? Or, should I release it inside the block? that seems weird. Thanks for any suggestions.

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烂柯人 2024-11-13 04:50:27

当一个块引用一个 Objective-C 对象时，例如：

Worker *myWorker = [[Worker alloc] init];
[work doAsyncStuffWithBlock:^(NSMutableDictionary *info)
{
    NSLog(@"processing info results");
    [myWorker doSomething];
}];
[myWorker release];

它会自动保留该对象，并且当块被释放时，它会自动释放该对象。

所以，是的，您应该在代码中释放 myWorker ，不，您不应该在块内释放 myWorker 。

When a block references an Objective-C object, e.g.:

Worker *myWorker = [[Worker alloc] init];
[work doAsyncStuffWithBlock:^(NSMutableDictionary *info)
{
    NSLog(@"processing info results");
    [myWorker doSomething];
}];
[myWorker release];

it automatically retains that object and, when the block is released, it automatically releases that object.

So yes, you should release myWorker in your code, and no, you shouldn’t release myWorker inside the block.

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