如何访问 XAML 网格视图的选定行中的信息？

发布于 2024-11-06 03:14:22 字数 1034 浏览 1 评论 0原文

我有一个列表视图，里面有一个网格视图，它绑定到一个自定义对象列表。在一个单元格中，我有三个可以在之间交换的元素，其中之一是带有单击事件的超链接。

当我转到超链接上的单击事件时，如何访问绑定在同一行中的“公司名称”？

这个问题可能与我的 ASP.Net 背景有关 - 我对 WPF 非常陌生。

<GridViewColumn Header="File" Width="100" DisplayMemberBinding="{Binding Path=CompanyFile}"/>
<GridViewColumn Header="Action" Width="300">
    <GridViewColumn.CellTemplate>
        <DataTemplate>
            <StackPanel>
                <TextBlock Text="{Binding Path=Status}" Visibility="{Binding Path=StatusVisibility}"></TextBlock>
                <TextBlock Visibility="{Binding Path=ButtonVisibility}"><Hyperlink Click="Hyperlink_Click"><TextBlock Text="{Binding Path=Button}"></TextBlock></Hyperlink></TextBlock>
                <ProgressBar Value="{Binding Path=Progress}" Visibility="{Binding Path=ProgressVisibility}"/>
            </StackPanel>
        </DataTemplate>
    </GridViewColumn.CellTemplate>
</GridViewColumn>

原文

I have a listview with a gridview inside it and it is bound to a list of custom objects. In one cell I have three elements that I swap between, one of which is a hyperlink with a click event.

How do I get access to the 'CompanyName' that is bound in the same row when I go to the click event on the hyperlink?

This question may bely my ASP.Net background - I am very new to WPF.

<GridViewColumn Header="File" Width="100" DisplayMemberBinding="{Binding Path=CompanyFile}"/>
<GridViewColumn Header="Action" Width="300">
    <GridViewColumn.CellTemplate>
        <DataTemplate>
            <StackPanel>
                <TextBlock Text="{Binding Path=Status}" Visibility="{Binding Path=StatusVisibility}"></TextBlock>
                <TextBlock Visibility="{Binding Path=ButtonVisibility}"><Hyperlink Click="Hyperlink_Click"><TextBlock Text="{Binding Path=Button}"></TextBlock></Hyperlink></TextBlock>
                <ProgressBar Value="{Binding Path=Progress}" Visibility="{Binding Path=ProgressVisibility}"/>
            </StackPanel>
        </DataTemplate>
    </GridViewColumn.CellTemplate>
</GridViewColumn>

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变身佩奇 2024-11-13 03:14:22

Hyperlink 继承了父 ListViewItem 的 DataContext，因此您只需对其进行强制转换：

void Hyperlink_Click(object sender, EventArgs e)
{
    Hyperlink link = (Hyperlink)sender;
    MyCustomObject obj = (MyCustomObject)link.DataContext;
    string companyName = obj.CompanyName;
    ...
}

另一种选择是绑定超链接的 Command 属性传递给 DataContext 上的命令，而不是显式处理 Click 事件。这有助于将视图与业务相关的代码解耦，并且这是在 MVVM 模式。

The Hyperlink inherits the DataContext of the parent ListViewItem, so you just need to cast it:

void Hyperlink_Click(object sender, EventArgs e)
{
    Hyperlink link = (Hyperlink)sender;
    MyCustomObject obj = (MyCustomObject)link.DataContext;
    string companyName = obj.CompanyName;
    ...
}

Another option is to bind the hyperlink's Command property to a command on your DataContext, rather than handling the Click event explicitly. This helps decoupling the view from the business-related code, and it's the usual way of doing things in the MVVM pattern.

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