如何防止通过 PHP mail() 发送的邮件成为垃圾邮件？

Question

我正在使用 PHP 的 mail() 函数发送电子邮件（sendmail 进程正在运行）。但所有邮件都会变成垃圾邮件（对于 gmail）。我已经尝试了很多在网上找到的技巧，但没有一个有效，请告诉我任何可靠的技巧。

Answer 1

您必须添加针头：

示例代码：

$headers = "From: [email protected]\r\n";
$headers .= "Reply-To: [email protected]\r\n";
$headers .= "Return-Path: [email protected]\r\n";
$headers .= "CC: [email protected]\r\n";
$headers .= "BCC: [email protected]\r\n";

if ( mail($to,$subject,$message,$headers) ) {
   echo "The email has been sent!";
   } else {
   echo "The email has failed!";
   }
?> 

Answer 2

没有确定的投篮技巧。您需要探究您的邮件被归类为垃圾邮件的原因。 SpamAssassin 有一个页面描述为合法发件人避免误报的一些提示。另请参阅编码恐怖：所以你想发送一些电子邮件（通过代码）

Answer 3

<?php

$subject = "this is a subject";
$message = "testing a message";
  


  // declare variable
  $headers = "Reply-To: The Sender <[email protected]>\r\n";

  // add more info
  $headers .= "Return-Path: The Sender <[email protected]>\r\n"; 
  $headers .= "From: The Sender <[email protected]>\r\n";  
  $headers .= "Organization: Sender Organization\r\n";
  $headers .= "MIME-Version: 1.0\r\n";
  $headers .= "Content-type: text/plain; charset=iso-8859-1\r\n";
  $headers .= "X-Priority: 3\r\n";
  $headers .= "X-Mailer: PHP". phpversion() ."\r\n" ;

  
  
mail("[email protected]", $subject, $message, $headers); 


?> 

Answer 4

尝试 PHP 邮件程序库。
或者通过 SMTP 发送邮件，在发送前对其进行过滤。
另外尝试提供所有详细信息，例如 FROM、return-path。

Answer 5

$fromMail = 'set your from mail';
$boundary = str_replace(" ", "", date('l jS \of F Y h i s A'));
$subjectMail = "New design submitted by " . $userDisplayName;


$contentHtml = '<div>Dear Admin<br /><br />The following design is submitted by '. $userName .'.<br /><br /><a href="'.$sdLink.'"><b>Click here</b></a> to check the design.</div>';
$contentHtml .= '<div><a href="'.$imageUrl.'"><img src="'.$imageUrl.'" width="250" height="95" border="0" alt="my picture"></a></div>';
$contentHtml .= '<div>Name : '.$name.'<br />Description : '. $description .'</div>';

$headersMail = '';
$headersMail .= 'From: ' . $fromMail . "\r\n" . 'Reply-To: ' . $fromMail . "\r\n";
$headersMail .= 'Return-Path: ' . $fromMail . "\r\n";
$headersMail .= 'MIME-Version: 1.0' . "\r\n";
$headersMail .= "Content-Type: multipart/alternative; boundary = \"" . $boundary . "\"\r\n\r\n";
$headersMail .= '--' . $boundary . "\r\n";
$headersMail .= 'Content-Type: text/html; charset=ISO-8859-1' . "\r\n";
$headersMail .= 'Content-Transfer-Encoding: base64' . "\r\n\r\n";
$headersMail .= rtrim(chunk_split(base64_encode($contentHtml)));

try {
    if (mail($toMail, $subjectMail, "", $headersMail)) {
        $status = 'success';
        $msg = 'Mail sent successfully.';
    } else {
        $status = 'failed';
        $msg = 'Unable to send mail.';
    }
} catch(Exception $e) {
    $msg = $e->getMessage();
}

这对我来说效果很好。它包括带有图像和链接的邮件，适用于各种邮件 ID。线索是完美地使用所有标题。

如果您从本地主机测试它，请在检查之前设置以下内容：

如何设置从本地主机 xampp 发送的邮件：

1. 注释 D:/xampp/sendmail/sendmail.ini 中的所有内容并提及下面在

   [发送邮件]

   smtp_server=smtp.gmail.com
   smtp_端口=587
   error_logfile=错误.log
   debug_logfile=调试.log
   [电子邮件受保护]
   auth_password=您的邮件密码
   [电子邮件受保护]

2. 在 D:/xampp/php/php.ini
   一个。下

   [邮件功能]

   SMTP = smtp.gmail.com
   smtp_port = 587

587设置 sendmail_from = [电子邮件受保护]
c.取消注释 sendmail_path = "\"D:\xamp\sendmail\sendmail.exe\" -t"
因此它应该如下所示

sendmail_path = "\"D:\xamp\sendmail\sendmail.exe\" -t"

。评论 sendmail_path="D:\xamp\mailtodisk\mailtodisk.exe"
因此它应该如下所示

;sendmail_path="D:\xamp\mailtodisk\mailtodisk.exe"

。 mail.add_x_header=关闭

Answer 6

<?php 
$to1 = '[email protected]';
$subject = 'Tester subject'; 

    // To send HTML mail, the Content-type header must be set

    $headers .= "Reply-To: The Sender <[email protected]>\r\n"; 
    $headers .= "Return-Path: The Sender <[email protected]>\r\n"; 
    $headers .= "From: [email protected]" ."\r\n" .
    $headers .= "Organization: Sender Organization\r\n";
    $headers .= "MIME-Version: 1.0\r\n";
    $headers .= "Content-type: text/html; charset=utf-8\r\n";
    $headers .= "X-Priority: 3\r\n";
    $headers .= "X-Mailer: PHP". phpversion() ."\r\n" ;
?>