是什么原因导致 substr 失败？
简单的 substr 调用无法正常运行。我只想抓取以正斜杠结尾的字符串。这里有七个字符串。
HELLO/NN, SMILE/JJ, JUMP/, GOOD/RB, GREAT/JJ, HAPPY/NNP, SEAPORT/
$m = substr($string, -1);
if ($m = "/") {
echo $string;
}
这段代码每次都会以某种方式返回 true。七个字全部打印出来。 我尝试过 strrev 和许多其他字符串函数。似乎没有 事情。我可以从字面上打印 $m 并看到它是“/”，但是 if 语句 确定每个单词都满足 $m = "/" 标准。即使 $m 不是“/”
A simple substr call is not functioning properly. I want to grab only the strings which end with a forward slash. Here are seven strings.
HELLO/NN, SMILE/JJ, JUMP/, GOOD/RB, GREAT/JJ, HAPPY/NNP, SEAPORT/
$m = substr($string, -1);
if ($m = "/") {
echo $string;
}
This code somehow returns true every time. All seven words are printed.
I've tried strrev and many other string functions. It doesn't seem to
matter. I can literally print $m and see that it's "/" but the if statement
decides that every word meets the $m = "/" criteria. Even when $m is not a "/"
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评论（3）
比较运算符是
==，而不是=：The comparison operator is
==, not=:难道不应该是
==而不是=吗？Shouldn't that be
==rather than=?您将值“/”分配给 $m 并且该评估返回 true。您想要比较并且应该使用
You are assigning the value "/" to $m and that evaluation returns true. You want to compare and should use