NSString 和连接的问题

发布于 2024-11-05 23:28:18 字数 528 浏览 2 评论 0原文

为什么这段代码给我以下错误？

“使用未声明的标识符baseURL”

和

“意外的接口名称 NSString，预期的表达式”

这里是整个代码块

switch (type) {
    case 1:
        NSString *baseURL = [NSString stringWithString:@"http://www.myserver.net/somephp/"];
        NSString *finalURL = [baseURL stringByAppendingString:@"?i="];
        break;
    case 2:
        NSString *finalURL = [baseURL stringByAppendingString:@"?n="];
        break;
    default:
        break;
}

原文

Why this code gives me the following errors?

"use of undeclared identifier baseURL"

and

"Unexpected Interface name NSString, expected expression"

here is the entire block of code

switch (type) {
    case 1:
        NSString *baseURL = [NSString stringWithString:@"http://www.myserver.net/somephp/"];
        NSString *finalURL = [baseURL stringByAppendingString:@"?i="];
        break;
    case 2:
        NSString *finalURL = [baseURL stringByAppendingString:@"?n="];
        break;
    default:
        break;
}

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去了角落 2024-11-12 23:28:18

听起来这些行位于 switch 语句内。如果是这种情况，请将字符串声明移到 switch 语句之外。

NSString *baseURL;
NSString *finalURL;
switch (<expression>) {
    case <constant>:
        baseURL = [NSString stringWithString:@"http://www.myserver.net/somephp"];
        finalURL = [baseURL stringByAppendingString:@"?i="];
        break;
    default:
        break;
}

有关解决此问题的更多信息和其他技术此问题。

Sounds like those lines are within a switch statement. If this is the case, move the declaration of the strings outside the switch statement.

NSString *baseURL;
NSString *finalURL;
switch (<expression>) {
    case <constant>:
        baseURL = [NSString stringWithString:@"http://www.myserver.net/somephp"];
        finalURL = [baseURL stringByAppendingString:@"?i="];
        break;
    default:
        break;
}

More information and other techniques to work around this on this question.

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