在 AS3 中维护两点之间的 lineTo 最有效的方法是什么？

发布于 2024-11-05 19:22:46 字数 380 浏览 1 评论 0原文

我正在寻找一种最有效的方法来维持 AS3 中两点与一条线的连接。基本上，我有一大堆四处移动的圆圈，并且有一个属性 subNode ，它将充当线条的终点。

目前，我的做法非常密集：

if(_line != null) _line.parent.removeChild(_line);

_line = new Sprite();
_line.graphics.lineStyle(1, 0xE1164B);
_line.graphics.lineTo(subNode.x - x, subNode.y - y);

addChild(_line);

是否可能只是一个 redrawLine() 或者我缺少的东西？

原文

I'm looking to work out the most efficient way to maintain the joining of two points with a line in AS3. Basically, I have a whole bunch of circles that move around, and have a property subNode which will act as an end point for the line.

At the moment, the way I'm doing it is extremely intensive:

if(_line != null) _line.parent.removeChild(_line);

_line = new Sprite();
_line.graphics.lineStyle(1, 0xE1164B);
_line.graphics.lineTo(subNode.x - x, subNode.y - y);

addChild(_line);

Is there maybe just a redrawLine() or something that I'm missing?

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嘿哥们儿 2024-11-12 19:22:46

您不必每次都实例化 Sprite。在这种情况下，Shape 也应该足够了。

if(_line == null) {
   _line = addChild(new Shape()) as Shape;
}

_line.graphics.clear();
_line.graphics.lineStyle(1, 0xE1164B);
_line.graphics.lineTo(subNode.x - x, subNode.y - y);

您还应该考虑何时划清界限。也许只有当子节点移动时。但没有足够的代码来正确回答这个问题。

You don't have to instantiate a Sprite every time. Also a Shape should be enough in this case.

if(_line == null) {
   _line = addChild(new Shape()) as Shape;
}

_line.graphics.clear();
_line.graphics.lineStyle(1, 0xE1164B);
_line.graphics.lineTo(subNode.x - x, subNode.y - y);

Also you should think about when to draw the line. Maybe only if the subNode hase moved. But there is not enough code for a proper answer to that.

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