jodatime 天周期类型问题/错误
我的 jodatime api 有问题。我不明白为什么这个测试不起作用。我需要确定 X 毫秒内有多少天、小时、分钟和秒。但天数尚未解决......有什么想法吗？
@Test
public void testTime() {
long secs = 3866 * 24 * 35;
long msecs = secs * 1000;
//Period period = duration.toPeriod();
PeriodType periodType = PeriodType.forFields(
new DurationFieldType[]{
DurationFieldType.days(),
DurationFieldType.hours(),
DurationFieldType.minutes(),
DurationFieldType.seconds(),
});
Duration duration = Duration.standardSeconds(secs);
Period period = duration.toPeriod(periodType, GregorianChronology.getInstance());
System.out.println("days:" + period.getDays());
System.out.println("hours:" + period.getHours());
System.out.println("mins:" + period.getMinutes());
System.out.println("seconds:" + period.getSeconds());
PeriodFormatter periodFormatter = new PeriodFormatterBuilder()
.printZeroAlways()
.minimumPrintedDigits(2)
.appendDays()
.appendSeparator(":")
.appendHours()
.appendSeparator(":")
.appendMinutes()
.appendSeparator(":")
.appendSecondsWithOptionalMillis()
.toFormatter();
StringBuffer stringBuffer = new StringBuffer();
periodFormatter.printTo(stringBuffer, period);
System.out.println(">>>" + stringBuffer);
}
输出是 天数：0 小时：902 分钟：4 秒:0 00:902:04:00
I have a problem with jodatime api. I can't understand why this test doesn't works. I need resolve how many days, hours, mins and seconds I have in X milliseconds. But the days value aren't resolved.... any idea?
@Test
public void testTime() {
long secs = 3866 * 24 * 35;
long msecs = secs * 1000;
//Period period = duration.toPeriod();
PeriodType periodType = PeriodType.forFields(
new DurationFieldType[]{
DurationFieldType.days(),
DurationFieldType.hours(),
DurationFieldType.minutes(),
DurationFieldType.seconds(),
});
Duration duration = Duration.standardSeconds(secs);
Period period = duration.toPeriod(periodType, GregorianChronology.getInstance());
System.out.println("days:" + period.getDays());
System.out.println("hours:" + period.getHours());
System.out.println("mins:" + period.getMinutes());
System.out.println("seconds:" + period.getSeconds());
PeriodFormatter periodFormatter = new PeriodFormatterBuilder()
.printZeroAlways()
.minimumPrintedDigits(2)
.appendDays()
.appendSeparator(":")
.appendHours()
.appendSeparator(":")
.appendMinutes()
.appendSeparator(":")
.appendSecondsWithOptionalMillis()
.toFormatter();
StringBuffer stringBuffer = new StringBuffer();
periodFormatter.printTo(stringBuffer, period);
System.out.println(">>>" + stringBuffer);
}
the output is
days:0
hours:902
mins:4
seconds:0
00:902:04:00
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评论（2）
您需要使用以下方法标准化周期：
或
然后您可以使用 normalizedPeriod 并查看您正在寻找的结果。
作为快速测试，我修改了您的 junit 测试用例并添加了这一行：
在您根据持续时间创建周期之后。
You need to normalize the period using:
or
Then you can use the normalizedPeriod and see the results you are looking for.
As a quick test I modified your junit test case and added the line:
right after your create the period from the duration.
您使用的年表可能认为天数并不准确。尝试使用 IOSChronology.getInstanceUTC()，而不是 GregorianChronology。
The chronology that you are using may not consider days to be precise. Instead of GregorianChronology, try using
IOSChronology.getInstanceUTC().