Python - 轻松将文本文件内容转换为字典值/键

发布于 2024-11-05 17:28:36 字数 256 浏览 0 评论 0原文

假设我有一个包含以下内容的文本文件：

line = "this is line 1"
line2 = "this is the second line"
line3 = "here is another line"
line4 = "yet another line!"

我想将它们快速转换为字典键/值，其中“ line* ”为键，引号中的文本为值，同时删除等号。

在 Python 中执行此操作的最佳方法是什么？

原文

Let's say I have a text file with the following:

line = "this is line 1"
line2 = "this is the second line"
line3 = "here is another line"
line4 = "yet another line!"

And I want to quickly convert these into dictionary keys/values with " line* " being the key and the text in quotes as the value while also removing the equals sign.

What would be the best way to do this in Python?

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奢华的一滴泪 2024-11-12 17:28:36

f = open(filepath, 'r')
answer = {}
for line in f:
    k, v = line.strip().split('=')
    answer[k.strip()] = v.strip()

f.close()

希望这有帮助

f = open(filepath, 'r')
answer = {}
for line in f:
    k, v = line.strip().split('=')
    answer[k.strip()] = v.strip()

f.close()

Hope this helps

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嘿看小鸭子会跑 2024-11-12 17:28:36

一行：

d = dict((line.strip().split(' = ') for line in file(filename)))

In one line:

d = dict((line.strip().split(' = ') for line in file(filename)))

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关于从前 2024-11-12 17:28:36

InspectorG4dget 的 urlopen 版本的答案可能如下所示：

from urllib.request import urlopen
url = 'https://raw.githubusercontent.com/sedeh/github.io/master/resources/states.txt'
response = urlopen(url)
lines = response.readlines()
state_names_dict = {}
for line in lines:
    state_code, state_name = line.decode().split(":")
    state_names_dict[state_code.strip()] = state_name.strip()

Here's what the urlopen version of inspectorG4dget's answer might look like:

from urllib.request import urlopen
url = 'https://raw.githubusercontent.com/sedeh/github.io/master/resources/states.txt'
response = urlopen(url)
lines = response.readlines()
state_names_dict = {}
for line in lines:
    state_code, state_name = line.decode().split(":")
    state_names_dict[state_code.strip()] = state_name.strip()

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~没有更多了~