C 递归程序无法使用 GCC 进行编译

发布于 2024-11-05 14:18:49 字数 302 浏览 1 评论 0原文

#include <stdio.h>

int main (void)

{
int n, x;

int factorial (int n)
{
if (x<=0)
{
 printf("x equals: ");
return 1;
}
else
{
return n * factorial (n-1); 
}
f(x)=f(x-1)+2; //says error is here
}
return 0;
}

我尝试过一些事情但无法让它发挥作用。我可能只是太累了，忽略了最小的事情，但非常感谢您的帮助！谢谢：）

原文

#include <stdio.h>

int main (void)

{
int n, x;

int factorial (int n)
{
if (x<=0)
{
 printf("x equals: ");
return 1;
}
else
{
return n * factorial (n-1); 
}
f(x)=f(x-1)+2; //says error is here
}
return 0;
}

I've tried some things and can't get it to work. I could just be overtired and looking past the smallest thing but help would be much appreciated! Thanks :)

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将军与妓 2024-11-12 14:18:49

您不能在 main() 或任何其他函数内部声明函数定义...函数定义必须是独立的，并且不能在其中嵌入函数定义。

另外，我不确定您在标记为错误的行上做了什么，因为 f() 不是已定义的函数，因此您无法调用它。此外，它需要返回某种类型的左值，例如指向函数内部声明的静态变量的指针，或者通过引用传递给函数的指针，即使如此，语法也不正确，因为需要取消引用...所以基本上你不能做你在那条线上所做的事情。

要获得可以编译的东西，请尝试

#include <stdio.h>

int factorial (int n)
{
    if (n <= 0)
    {
        return 1;
    }
    else
    {
        return n * factorial (n-1); 
    }
}

int main (void)
{
    int x;

    x = factorial(5);
    printf("Factorial of 5 is equal to %d", x);

    return 0;
}

You cannot declare a function definition inside of main() or any other function ... function definitions have to be stand-alone and cannot have embedded function definitions inside of them.

Also I'm not sure what you're doing on the line that you've marked as an error since f() is not a defined function, so you can't call it. Furthermore, it would need to return some type of l-value, such as a pointer to a static variable declared inside the function, or a pointer passed by reference to the function and even then the syntax is not right since there would be a required dereference ... so basically you can't do what you're doing on that line.

To get something that compiles, try

#include <stdio.h>

int factorial (int n)
{
    if (n <= 0)
    {
        return 1;
    }
    else
    {
        return n * factorial (n-1); 
    }
}

int main (void)
{
    int x;

    x = factorial(5);
    printf("Factorial of 5 is equal to %d", x);

    return 0;
}

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溺孤伤于心 2024-11-12 14:18:49

使用缩进来查看范围可能存在的问题：

 #include <stdio.h>

int main (void)
{
    int n, x;

int factorial (int n)
{
    if (x<=0)
    {
        printf("x equals: ");
        return 1;
    }
    else
    {
        return n * factorial (n-1); 
    }
    f(x)=f(x-1)+2; //says error is here
}
return 0;

}

据我所知，C 没有闭包。

Use indentation to see possible problems with scope:

 #include <stdio.h>

int main (void)
{
    int n, x;

int factorial (int n)
{
    if (x<=0)
    {
        printf("x equals: ");
        return 1;
    }
    else
    {
        return n * factorial (n-1); 
    }
    f(x)=f(x-1)+2; //says error is here
}
return 0;

}

As far as I can remember, C doesn't have closures.

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