弹出后强制推送到页面

发布于 2024-11-05 13:59:26 字数 304 浏览 0 评论 0原文

我有一个屏幕，用户可以在其中创建登录名并按保存按钮。此时，我弹回到前一个屏幕，其中充满了保存的登录信息，如下所示...

[self.navigationController popViewControllerAnimated:YES];

但是，仅在这种情况下（一旦他们按下“保存”），我想自动将用户推送到另一个屏幕（使用他们刚刚登录）。这是为了确保如果用户返回屏幕，他们会返回到登录列表，而不是“创建新登录”屏幕。

我的问题是在这种情况下如何强制推动？我能否以某种方式使登录页面识别用户刚刚成功登录回来的时间？

原文

I have a screen where the user creates a login and presses the save button. At this point I pop back to the previous screen full of saved logins like this ...

[self.navigationController popViewControllerAnimated:YES];

However, in this scenario only (once they have pressed save), I want to automatically push the user to another screen (effectively logging them in using the login they just made). This is to ensure that if the user goes back a screen, they return to the list of logins and not to the 'create new login' screen.

My question is how can I force this push in this scenario? Can I somehow make the logins page recognise when the user has just come back from successfully making a login?

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栩栩如生 2024-11-12 13:59:26

-(void)viewWillAppear:(BOOL)animated
{

if(isLoggedIn)
{
//Do something
}
else
{
//Show login
}
}

或者如果您使用集中式导航控制器
您可以在登录视图控制器中执行此操作

- (IBAction)saveButtonPressed
{
[yourAppDelegate.mainNavigationController popViewControllerAnimated:YES];
[yourAppDelegate.mainNavigationController pushViewController:nextView animated:YES];

}

-(void)viewWillAppear:(BOOL)animated
{

if(isLoggedIn)
{
//Do something
}
else
{
//Show login
}
}

Or if you are using a centralized navigation controller
you can do this in your login view controller

- (IBAction)saveButtonPressed
{
[yourAppDelegate.mainNavigationController popViewControllerAnimated:YES];
[yourAppDelegate.mainNavigationController pushViewController:nextView animated:YES];

}

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