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将当前时间与固定时间 05:00:00 PM 进行比较

发布于 2024-11-05 13:37:52 字数 97 浏览 4 评论 0原文

我如何将当前时间 [NSDate date] 与固定时间 05:00:00 PM 进行比较。

那个 05:00 PM 是否已经过去了。我只需要 BOOL 检查这个。

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哆啦不做梦 2024-11-12 13:37:52

- (BOOL)past5pm
{
    NSCalendar *gregorianCalender = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
    NSDateComponents *components = [gregorianCalender components:NSHourCalendarUnit fromDate:[NSDate date]];

    if([components hour] >= 17) // NSDateComponents uses the 24 hours format in which 17 is 5pm
       return YES;

    return NO;
}

- (BOOL)past5pm
{
    NSCalendar *gregorianCalender = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
    NSDateComponents *components = [gregorianCalender components:NSHourCalendarUnit fromDate:[NSDate date]];

    if([components hour] >= 17) // NSDateComponents uses the 24 hours format in which 17 is 5pm
       return YES;

    return NO;
}

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锦爱 2024-11-12 13:37:52

NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init]  autorelease];
[dateFormatter setDateFormat:@"HH.mm"];
NSDate *currentDate = [NSDate date];
NSString *curDate = [dateFormatter stringFromDate:currentDate];

if ([curDate doubleValue] >= 17.00) 
{
    //set your bool
}

NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init]  autorelease];
[dateFormatter setDateFormat:@"HH.mm"];
NSDate *currentDate = [NSDate date];
NSString *curDate = [dateFormatter stringFromDate:currentDate];

if ([curDate doubleValue] >= 17.00) 
{
    //set your bool
}

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丑疤怪 2024-11-12 13:37:52

试试这个

NSDateFormatter* dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
        [dateFormatter setDateFormat:@"hh:mm:ss a"];

        NSDate* date = [NSDate date];

        //Get the string date
        NSString* str = [dateFormatter stringFromDate:date];

        NSDate *firstDate = [dateFormatter dateFromString:@"05:00:00 PM"];

        NSDate *secondDate = [dateFormatter dateFromString:str];

        NSTimeInterval timeDifference = [secondDate timeIntervalSinceDate:firstDate];

        NSLog(@"Time Diff - %f",timeDifference);

Try this

NSDateFormatter* dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
        [dateFormatter setDateFormat:@"hh:mm:ss a"];

        NSDate* date = [NSDate date];

        //Get the string date
        NSString* str = [dateFormatter stringFromDate:date];

        NSDate *firstDate = [dateFormatter dateFromString:@"05:00:00 PM"];

        NSDate *secondDate = [dateFormatter dateFromString:str];

        NSTimeInterval timeDifference = [secondDate timeIntervalSinceDate:firstDate];

        NSLog(@"Time Diff - %f",timeDifference);

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帅气尐潴 2024-11-12 13:37:52

您可以使用纯 C 风格代码并以整数形式获取差异，然后根据差异是正数还是负数决定需要从比较函数返回什么。您也可以通过这种方式比较分钟数。不要忘记导入 time.h。

    time_t now = time(NULL);
    struct tm oldCTime;
    localtime_r(&now, &oldCTime);
    int hours = oldCTime.tm_hour;
    int diff = 17-hours;
    NSLog(@"Time difference is: %d.", diff);

You can probably use plain C style code and get the difference as an integer and then decide what you need to return from the comparison function depending on wether the difference is positive or negative. You can compare minutes this way as well. Dont forget to import time.h.

    time_t now = time(NULL);
    struct tm oldCTime;
    localtime_r(&now, &oldCTime);
    int hours = oldCTime.tm_hour;
    int diff = 17-hours;
    NSLog(@"Time difference is: %d.", diff);

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