iPhone：无法创建 URL

发布于 2024-11-05 00:48:03 字数 435 浏览 1 评论 0原文

我正在使用 facebook apis

我正在尝试获取 id 为“105502842870274”的图像的属性，为此我尝试创建一个像这样的 url

NSString *firstComponent=@"https://graph.facebook.com/105502842870274?access_token=";
firstComponent=[firstComponent stringByAppendingFormat:[NSString stringWithFormat:@"%@",_accessToken]];

NSURL *url = [NSURL URLWithString:firstComponent];

，但每次 url 都传递为 nil。

如果我做错了什么或建议其他方式来获取图像的属性，请告诉我。

提前感谢

原文

I am working with facebook apis

I am trying to fetch attributes of an image with id '105502842870274' for this I tried to create a url like this

NSString *firstComponent=@"https://graph.facebook.com/105502842870274?access_token=";
firstComponent=[firstComponent stringByAppendingFormat:[NSString stringWithFormat:@"%@",_accessToken]];

NSURL *url = [NSURL URLWithString:firstComponent];

but every time url is passes as nil.

Please let me know if I am doing something wrong or suggest someother way to fetch attributes of an image.

Thanx in advance

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虫児飞 2024-11-12 00:48:03

这将解决您的问题。其html编码问题。

firstComponent = [firstComponent stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding];

另请参阅：参考页面

this will resolve your issue. Its html encoding problem.

firstComponent = [firstComponent stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding];

also look: reference page

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面犯桃花 2024-11-12 00:48:03

试试这个

NSString *firstComponent=@"https://graph.facebook.com/105502842870274?access_token=";
firstComponent=[firstComponent stringByAppendingString:[NSString stringWithFormat:@"%@",_accessToken]];

NSURL *url = [NSURL URLWithString:firstComponent];

try this

NSString *firstComponent=@"https://graph.facebook.com/105502842870274?access_token=";
firstComponent=[firstComponent stringByAppendingString:[NSString stringWithFormat:@"%@",_accessToken]];

NSURL *url = [NSURL URLWithString:firstComponent];

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醉南桥 2024-11-12 00:48:03

你只是做得太复杂了，而且你在额外的代码中犯了错误。

您使用了 stringByAppendingFormat 而不是 stringByAppendingString。

对于更简单的解决方案，只需执行以下操作：

NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"https://graph.facebook.com/105502842870274?access_token=%@", _accessToken]];

或者如果您想稍后访问该字符串：

NSString* firstComponent = [NSString stringWithFormat:@"https://graph.facebook.com/105502842870274?access_token=%@", _accessToken]
NSURL* url = [NSURL URLWithString:firstComponent];

You're just doing it too complicated, and it is in your extra code that you made an error.

You used stringByAppendingFormat instead of stringByAppendingString.

For an even easier solution, just do :

NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"https://graph.facebook.com/105502842870274?access_token=%@", _accessToken]];

Or if you want to access the string later :

NSString* firstComponent = [NSString stringWithFormat:@"https://graph.facebook.com/105502842870274?access_token=%@", _accessToken]
NSURL* url = [NSURL URLWithString:firstComponent];

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