PHP 中的编辑
我已经在模型中编写了这些函数（我正在使用 CodeIgniter）。
function getLocalIngrdname()
{
$this->load->database();
$query = $this->db->get('onl_local_ingrd');
foreach($query->result() as $row)
$allingrd[]=$row->ingrd_localname;
return $allingrd;
}
function getCloseIngrdname($ingrdname,$localname)
{
$this->load->database();
$query = $this->db->get('onl_ingrd');
foreach($query->result() as $row)
$allingrd[]=$row->ingrd_name;
foreach($localname as $row)
$allingrd[]=$row;
$shortest=-1;
foreach ($allingrd as $ingrd) {
$lev = levenshtein($ingrdname, $ingrd);
if ($lev <= $shortest || $shortest < 0) {
$closeword = $ingrd;
$shortest = $lev;
}
}
return $closeword;
}
该函数位于控制器中
function getResult()
{
$this->load->model('searchRecipe_model');
$ingrdname = $this->input->post('ingrdname');
$output[]=2;
$localnames[]=$this->searchRecipe_model->getLocalIngrdname();
$output[]=$this->searchRecipe_model->getCloseIngrdname($ingrdname,$localnames);
echo json_encode($localnames);
}
$allingrd 是一个成分名称数组。我在 javascript 警报消息中显示 $closeword 。 如果我给出$lev=levenshtein($ingrdname,$allingrd[0])，它就可以完美工作；但是，它不在循环中工作。有什么想法吗？提前致谢。
I have written these function in a model (I am using CodeIgniter).
function getLocalIngrdname()
{
$this->load->database();
$query = $this->db->get('onl_local_ingrd');
foreach($query->result() as $row)
$allingrd[]=$row->ingrd_localname;
return $allingrd;
}
function getCloseIngrdname($ingrdname,$localname)
{
$this->load->database();
$query = $this->db->get('onl_ingrd');
foreach($query->result() as $row)
$allingrd[]=$row->ingrd_name;
foreach($localname as $row)
$allingrd[]=$row;
$shortest=-1;
foreach ($allingrd as $ingrd) {
$lev = levenshtein($ingrdname, $ingrd);
if ($lev <= $shortest || $shortest < 0) {
$closeword = $ingrd;
$shortest = $lev;
}
}
return $closeword;
}
This function is in controller
function getResult()
{
$this->load->model('searchRecipe_model');
$ingrdname = $this->input->post('ingrdname');
$output[]=2;
$localnames[]=$this->searchRecipe_model->getLocalIngrdname();
$output[]=$this->searchRecipe_model->getCloseIngrdname($ingrdname,$localnames);
echo json_encode($localnames);
}
$allingrd is an array of ingredient names. I display the $closeword in javascript alert message.
If I give$lev=levenshtein($ingrdname,$allingrd[0]) it works perfectly; however, it's not working in the loop. Any ideas as to why? Thanks in advance.
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也许您有一些长度超过 255 个字符的字符串？在这些情况下，levenshtein() 函数返回 -1，这意味着根据您的算法，最后一个此类字符串将始终是“最短的”。如果这是您的问题，您需要以这种方式丢弃 $lev 等于 -1 的值：
请注意，$closeword 可能并不总是被设置（例如，如果 $allingrd 中的所有字符串都超过 255 个字符，或者如果 $allingrd 为空）。不要忘记在循环之前将 $closeword 初始化为合理的值，例如 false、null 或空字符串。
Maybe you have som strings which are longer than 255 chars? The levenshtein() function returns -1 in those cases, which means the last such string will always be "the shortest" according to your algorithm. If this is your problem, you'll need to discard values where $lev equals -1 in this way:
Note that $closeword may not always be set (if, for example, all strings in $allingrd is longer than 255 chars, or if $allingrd is empty). Don't forget to initialise $closeword to something sensible before the loop, for example false, null or an empty string.
我认为你想要做的是：
现在 $closeword 是一个数组。您只是在每次循环运行时重新声明 $closeword 的值。现在，您将把值放入数组中。最短的美元也一样。
I think that what you're trying to do is:
Now $closeword is an array. You were just redeclaring the value of $closeword, for each time your loop was running. Now, you will throw the values inside an array. Same for $shortest.
请注意 PHP 的 levenshtein 页面上如何声明
$shortest为-1。这非常重要，否则您将永远无法满足if语句的要求。这应该可以解决问题。
Notice how on PHP's levenshtein page they declare
$shortestas-1. This is pretty important or else you'll never meet the requirements of theifstatement.This should do the trick.