为什么非静态方法有额外的Local？那是什么？

Question

根据我对方法 1 中定义的每个局部变量的理解，local 是为此 Locals 指示器添加的。

来源：

public class A {
    public void a() {}

    public static void b() {}
}

生成的字节码：

Compiled from "A.java"
public class A extends java.lang.Object
  SourceFile: "A.java"
  minor version: 0
  major version: 50
  Constant pool:
const #1 = Method       #3.#12; //  java/lang/Object."<init>":()V
const #2 = class        #13;    //  A
const #3 = class        #14;    //  java/lang/Object
const #4 = Asciz        <init>;
const #5 = Asciz        ()V;
const #6 = Asciz        Code;
const #7 = Asciz        LineNumberTable;
const #8 = Asciz        a;
const #9 = Asciz        b;
const #10 = Asciz       SourceFile;
const #11 = Asciz       A.java;
const #12 = NameAndType #4:#5;//  "<init>":()V
const #13 = Asciz       A;
const #14 = Asciz       java/lang/Object;

{
public A();
  Code:
   Stack=1, Locals=1, Args_size=1
   0:   aload_0
   1:   invokespecial   #1; //Method java/lang/Object."<init>":()V
   4:   return
  LineNumberTable:
   line 1: 0


public void a();
  Code:
   Stack=0, Locals=1, Args_size=1
   0:   return
  LineNumberTable:
   line 6: 0


public static void b();
  Code:
   Stack=0, Locals=0, Args_size=0
   0:   return
  LineNumberTable:
   line 11: 0


}

Answer 1

它是当前对象，又名 this。来自 JVM 规范第 §3.6.1 局部变量< /a>：

在实例方法调用时，局部变量 0 始终用于传递对正在调用实例方法的对象的引用（Java 编程语言中的 this ）。

Answer 2

我的猜测是这个