如果在 JavaScript 中未选中任何复选框，则需要显示警报，我当前的方法不起作用

发布于 2024-11-04 20:00:30 字数 444 浏览 0 评论 0原文

我收到“预期对象”错误 - 该错误指向第一个 If... 从我读到的有关复选框的所有内容（复选框对我来说永远不起作用）以及我读到的有关多个条件的内容，这是对的吗？尽管这不是...

var lucy = window.document.alice

if (lucy.ch1.checked != "true" && lucy.ch2.checked != "true" && lucy.ch3.checked != "true" && lucy.ch4.checked != "true")
{
    alert('Atleast one box must be checked');
}

if (lucy.skeletor.value = "no")
{
    alert('Default Option is not a valid selection.');
}

原文

I'm getting an error for "Object Expected" - the error points to the first If... from everything I read about checkboxes (checkboxes never work for me) and what I read about multiple conditionals, this is right? Even though it isn't...

var lucy = window.document.alice

if (lucy.ch1.checked != "true" && lucy.ch2.checked != "true" && lucy.ch3.checked != "true" && lucy.ch4.checked != "true")
{
    alert('Atleast one box must be checked');
}

if (lucy.skeletor.value = "no")
{
    alert('Default Option is not a valid selection.');
}

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神经暖 2024-11-11 20:00:30

您不需要 lucy.ch1.checked != "true" 部分。只需说 if (!lucy.ch1.checked && !lucy.ch2.checked && ...)。此外，使用 if，而不是 If，javascript 区分大小写。您的代码是失败的保证，因此也许您希望将其重写为以下内容：

var lucy = document.alice; //a form of some kind?
if (!lucy.ch1.checked && !lucy.ch2.checked 
    && !lucy.ch3.checked && !lucy.ch4.checked)
{
  alert('At least one box must be checked');
}

if (lucy.skeletor.value === "no")
{
  alert('Default Option is not a valid selection.');
}

You don't need the lucy.ch1.checked != "true" part. Just say if (!lucy.ch1.checked && !lucy.ch2.checked && ...). Furthermore use if, not If, javascript is case sensitive. Your code is a guarantee for failure, so maybe you want it to rewrite it to something like:

var lucy = document.alice; //a form of some kind?
if (!lucy.ch1.checked && !lucy.ch2.checked 
    && !lucy.ch3.checked && !lucy.ch4.checked)
{
  alert('At least one box must be checked');
}

if (lucy.skeletor.value === "no")
{
  alert('Default Option is not a valid selection.');
}

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两人的回忆 2024-11-11 20:00:30

尝试

if (!(lucy.ch1.checked || lucy.ch2.checked || lucy.ch3.checked))

Try

if (!(lucy.ch1.checked || lucy.ch2.checked || lucy.ch3.checked))

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青朷 2024-11-11 20:00:30

Javascript 区分大小写 - 您需要使用 if()

更新：这是我验证表单的方法（我不太可能将对象称为 lucy，但在这里您可以）：

function validate(lucy) {
  if (!lucy.ch1.checked && !lucy.ch2.checked && !lucy.ch3.checked && !lucy.ch4.checked) {
    alert('At least one box must be checked');
    return false;
  }
  if (lucy.skeletor.value = "no") {
    alert('Default Option is not a valid selection.');
    return false;
  }
  return true;
}

<form onsubmit="return validate(this)">

Javascript is case sensitive - you need to use if()

Update: here is a how I would validate a form (I would not likely call the obejct lucy, but here you go):

function validate(lucy) {
  if (!lucy.ch1.checked && !lucy.ch2.checked && !lucy.ch3.checked && !lucy.ch4.checked) {
    alert('At least one box must be checked');
    return false;
  }
  if (lucy.skeletor.value = "no") {
    alert('Default Option is not a valid selection.');
    return false;
  }
  return true;
}

<form onsubmit="return validate(this)">

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