$_POST 未设置
有谁知道为什么 $_POST 没有被设置？
这是一些代码。
<form method="post" name="form" id="clientForm" action="">
<input type="submit" name="sub" value="Delete_Checked"/>
<?php if ($i%2){ ?> class="even"<?php } ?>
<input type="checkbox" name="doc[]" value="<?php echo $document->doID; ?>"/>
<?php $i++; } ?>
</form>
<?php
if (isset($_POST['sub']) == 'Delete_Checked'){
print_r($_POST['sub']); // nothing gets print.......
}
?>
我一定是忽略了什么。
does anyone have any idea why $_POST not being set??
here is some of the code.
<form method="post" name="form" id="clientForm" action="">
<input type="submit" name="sub" value="Delete_Checked"/>
<?php if ($i%2){ ?> class="even"<?php } ?>
<input type="checkbox" name="doc[]" value="<?php echo $document->doID; ?>"/>
<?php $i++; } ?>
</form>
<?php
if (isset($_POST['sub']) == 'Delete_Checked'){
print_r($_POST['sub']); // nothing gets print.......
}
?>
i must be overlooking something.
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评论（3）
如果提交时未选中该复选框，则该复选框不会出现在 $_POST 数组中。
$_POST 本身总是被设置的。当您需要查看其中包含的所有内容时，请尝试此操作：
确保您也使用“post”作为表单方法。
此外，当您的代码仅显示 'doc[]` 输入时，您似乎正在尝试访问
$_POST['sub']。If the checkbox is not checked when submitted, it won't be in the $_POST array.
$_POST itself is always set. Try this instead when you need to see everything it contains:
Make sure you are using "post" as your form method as well.
Also, you seem to be trying to access
$_POST['sub']when your code only shows the 'doc[]` input.不应该这样写。它只会在偶然情况下起作用。
作者想写的是：
我个人会省略整个
isset部分，因为这正是阻碍您评估原因的原因。This is not how it should be written. It will only work by accident.
What the author wanted to write was:
I would personally leave out the whole
issetpart, because that's exactly what's obstructing your assessment of the cause.该输入应该在带有 POST 方法的表单内
<代码>
尝试将操作放入
action=""that input should be inside form with method POST
try to put the action to
action="<?php echo $_SERVER['PHP_SELF'];?>"