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XSLT 变量不起作用

发布于 2024-11-04 18:41:12 字数 1543 浏览 0 评论 0 原文

我有以下一段 XSLT 代码：

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml">

<xsl:variable name="condition">(coasts='Adriatic Sea')or(coasts='Mediterranean Sea')</xsl:variable>
<xsl:template match="cia">
    <html>
     <head></head>
     <body>
      <table border="1">
       <tr>
        <th>Country</th>
        <th>Capital</th>
        <th>Area</th>
        <th>Population</th>
        <th>Inflation rate</th>
       </tr> 
       <xsl:for-each select="country">
        <xsl:if test="{$condition}">
        <tr>
         <td>
          <xsl:value-of select="@name"/>
         </td>
         <td>
          <xsl:value-of select="@capital"/>
         </td> 
         <td>
          <xsl:value-of select="@total_area"/>
         </td> 
         <td>
          <xsl:value-of select="@population"/>
         </td> 
         <td>
          <xsl:value-of select="@inflation"/>
         </td>
        </tr>
        </xsl:if>
       </xsl:for-each>
      </table>
     </body>
    </html>
  </xsl:template> 
</xsl:stylesheet>

如果将条件表达式直接放入 if 元素中，代码可以正常工作，但是，我的问题是，当我将相同的条件表达式分配给变量，然后在 if 元素中引用它时，它不会不工作。我做错了什么吗？这可能吗？谢谢！

原文

I have the following piece of XSLT code:

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml">

<xsl:variable name="condition">(coasts='Adriatic Sea')or(coasts='Mediterranean Sea')</xsl:variable>
<xsl:template match="cia">
    <html>
     <head></head>
     <body>
      <table border="1">
       <tr>
        <th>Country</th>
        <th>Capital</th>
        <th>Area</th>
        <th>Population</th>
        <th>Inflation rate</th>
       </tr> 
       <xsl:for-each select="country">
        <xsl:if test="{$condition}">
        <tr>
         <td>
          <xsl:value-of select="@name"/>
         </td>
         <td>
          <xsl:value-of select="@capital"/>
         </td> 
         <td>
          <xsl:value-of select="@total_area"/>
         </td> 
         <td>
          <xsl:value-of select="@population"/>
         </td> 
         <td>
          <xsl:value-of select="@inflation"/>
         </td>
        </tr>
        </xsl:if>
       </xsl:for-each>
      </table>
     </body>
    </html>
  </xsl:template> 
</xsl:stylesheet>

If put the conditional expression directly in the if element the code works fine, however, my problem is that when I assign the same conditional expression to the variable and then reference it in the if element it doesn't work. Am I doing something wrong? Is this possible?
Thanks!

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情绪少女 2024-11-11 18:41:12

存在多个问题：

中的括号是不必要的；使用
使用以下 xsl:variable 构造：
```
;
```
当您的 xsl:if 中有条件时，将相对于每个 执行测试国家。顶级变量的情况并非如此。变量的值是表达式的结果，而不是表达式本身。如果您坚持使用变量，请在循环内初始化它。

请参阅以下样式表：

<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns="http://www.w3.org/1999/xhtml">
    <xsl:template match="cia">
        <html>
            <head></head>
            <body>
                <table border="1">
                    <tr>
                        <th>Country</th>
                        <th>Capital</th>
                        <th>Area</th>
                        <th>Population</th>
                        <th>Inflation rate</th>
                    </tr>
                    <xsl:for-each select="country">
                        <xsl:variable name="condition"
                            select="(coasts='Adriatic Sea') or 
                                    (coasts='Mediterranean Sea')" />
                        <xsl:if test="$condition">
                            <tr>
                                <td>
                                    <xsl:value-of select="@name" />
                                </td>
                                <td>
                                    <xsl:value-of select="@capital" />
                                </td>
                                <td>
                                    <xsl:value-of select="@total_area" />
                                </td>
                                <td>
                                    <xsl:value-of select="@population" />
                                </td>
                                <td>
                                    <xsl:value-of select="@inflation" />
                                </td>
                            </tr>
                        </xsl:if>
                    </xsl:for-each>
                </table>
            </body>
        </html>
    </xsl:template>
</xsl:stylesheet>

输入：

<cia>
    <country name="test1" inflation="22">
        <coasts>Adriatic Sea</coasts>
    </country>
    <country name="test2" inflation="7">
        <coasts>No match</coasts>
    </country>
</cia>

输出（仅第一个国家/地区 通过测试）：

<html xmlns="http://www.w3.org/1999/xhtml">
    <head></head>
    <body>
        <table border="1">
            <tr>
                <th>Country</th>
                <th>Capital</th>
                <th>Area</th>
                <th>Population</th>
                <th>Inflation rate</th>
            </tr>
            <tr>
                <td>test1</td>
                <td></td>
                <td></td>
                <td></td>
                <td>22</td>
            </tr>
        </table>
    </body>
</html>

请注意，您实际上甚至不需要单独的条件；只需添加一个即可。最好首先只选择所需的元素。该循环产生相同的输出：

<xsl:for-each
    select="country[(coasts='Adriatic Sea') or
                     coasts='Mediterranean Sea')]">
    <tr>
        <td>
            <xsl:value-of select="@name" />
        </td>
        <td>
            <xsl:value-of select="@capital" />
        </td>
        <td>
            <xsl:value-of select="@total_area" />
        </td>
        <td>
            <xsl:value-of select="@population" />
        </td>
        <td>
            <xsl:value-of select="@inflation" />
        </td>
    </tr>
</xsl:for-each>

There are multiple problems:

The brackets in <xsl:if test="{$condition}"> are unnecessary; use <xsl:if test="$condition">

Use the following xsl:variable construct:

<xsl:variable name="condition" 
        select="(coasts='Adriatic Sea')or(coasts='Mediterranean Sea')"/>

When you had the condition in your xsl:if the test was performed relative to each country. This is not the case in a top-level variable. The value of the variable is the result of the expression, not the expression itself. If you insist on a variable, then initialize it inside the loop.

See the following stylesheet:

<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns="http://www.w3.org/1999/xhtml">
    <xsl:template match="cia">
        <html>
            <head></head>
            <body>
                <table border="1">
                    <tr>
                        <th>Country</th>
                        <th>Capital</th>
                        <th>Area</th>
                        <th>Population</th>
                        <th>Inflation rate</th>
                    </tr>
                    <xsl:for-each select="country">
                        <xsl:variable name="condition"
                            select="(coasts='Adriatic Sea') or 
                                    (coasts='Mediterranean Sea')" />
                        <xsl:if test="$condition">
                            <tr>
                                <td>
                                    <xsl:value-of select="@name" />
                                </td>
                                <td>
                                    <xsl:value-of select="@capital" />
                                </td>
                                <td>
                                    <xsl:value-of select="@total_area" />
                                </td>
                                <td>
                                    <xsl:value-of select="@population" />
                                </td>
                                <td>
                                    <xsl:value-of select="@inflation" />
                                </td>
                            </tr>
                        </xsl:if>
                    </xsl:for-each>
                </table>
            </body>
        </html>
    </xsl:template>
</xsl:stylesheet>

Input:

<cia>
    <country name="test1" inflation="22">
        <coasts>Adriatic Sea</coasts>
    </country>
    <country name="test2" inflation="7">
        <coasts>No match</coasts>
    </country>
</cia>

Output (only the first country passes the test):

<html xmlns="http://www.w3.org/1999/xhtml">
    <head></head>
    <body>
        <table border="1">
            <tr>
                <th>Country</th>
                <th>Capital</th>
                <th>Area</th>
                <th>Population</th>
                <th>Inflation rate</th>
            </tr>
            <tr>
                <td>test1</td>
                <td></td>
                <td></td>
                <td></td>
                <td>22</td>
            </tr>
        </table>
    </body>
</html>

Note that you don't really even need a separate condition; it's better to select just the desired elements in the first place. This loop produces the same output:

<xsl:for-each
    select="country[(coasts='Adriatic Sea') or
                     coasts='Mediterranean Sea')]">
    <tr>
        <td>
            <xsl:value-of select="@name" />
        </td>
        <td>
            <xsl:value-of select="@capital" />
        </td>
        <td>
            <xsl:value-of select="@total_area" />
        </td>
        <td>
            <xsl:value-of select="@population" />
        </td>
        <td>
            <xsl:value-of select="@inflation" />
        </td>
    </tr>
</xsl:for-each>

回复收藏 0 原文

你列表最软的妹 2024-11-11 18:41:12

替换：

                <xsl:for-each select="country">

为

               <xsl:apply templates select="country"/>

另外，添加这些模板：

 <xsl:template match="country"/>

 <xsl:template match=
  "country[coasts='Adriatic Sea' 
         or                                        
           coasts='Mediterranean Sea'
         ]">
<xsl:template match=
  "country[coasts='Adriatic Sea'
         or
           coasts='Mediterranean Sea'
         ]">
    <tr>
        <td>
            <xsl:value-of select="@name"/>
        </td>
        <td>
            <xsl:value-of select="@capital"/>
        </td>
        <td>
            <xsl:value-of select="@total_area"/>
        </td>
        <td>
            <xsl:value-of select="@population"/>
        </td>
        <td>
            <xsl:value-of select="@inflation"/>
        </td>
    </tr>
</xsl:template>

您是否注意到“神奇地“消失了？

当然，该代码还可以进一步改进，但是您既没有提供要应用转换的 XML 文档的实例，也没有提供所需的输出。

Replace:

                <xsl:for-each select="country">

with

               <xsl:apply templates select="country"/>

also, add these templates:

 <xsl:template match="country"/>

 <xsl:template match=
  "country[coasts='Adriatic Sea' 
         or                                        
           coasts='Mediterranean Sea'
         ]">
<xsl:template match=
  "country[coasts='Adriatic Sea'
         or
           coasts='Mediterranean Sea'
         ]">
    <tr>
        <td>
            <xsl:value-of select="@name"/>
        </td>
        <td>
            <xsl:value-of select="@capital"/>
        </td>
        <td>
            <xsl:value-of select="@total_area"/>
        </td>
        <td>
            <xsl:value-of select="@population"/>
        </td>
        <td>
            <xsl:value-of select="@inflation"/>
        </td>
    </tr>
</xsl:template>

Did you note that the <xsl:if> "magically" disappeared?

Of course, this code can be improved even further, but you haven't provided neither an instance of the XML document on which the transformation is to be applied, nor the desired output.

回复收藏 0 原文

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